Given V₁ = 25/0° V and V₂ = 10236.87° V are connected in series. Find the resultant voltage V = V₁ + V2.(Take cos 36.87° = 0.8, and sin 36.87° = 0.6)O (17+j31) VO (6 + j33) VO (33+j6) V(33 + j19) V

Given voltages, V1=25∠0°.V2=10∠36.87°.

Given V₁ = 25/0° V and V₂ = 10236.87° V are connected in series. Find the resultant voltage Vs = V₁ + V₂. (Take cos 36.87° = 0.8, and sin 36.87° = 0.6) O (17+j31) V O (6 + j33) V O (33+j6) V O (33+j19) V

Given V₁ = 25/0° V and V₂ = 10236.87° V are connected in series. Find the resultant voltage Vs = V₁ + V₂. (Take cos 36.87° = 0.8, and sin 36.87° = 0.6) O (17+j31) V O (6 + j33) V O (33+j6) V O (33+j19) V

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.7P: Let a 100V sinusoidal source be connected to a series combination of a 3 resistor, an 8 inductor,...

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Concept explainers

Superposition Theorem

The superposition theorem is applied to linear systems. For such systems, the output from two different inputs equals the sum of the outputs from each input separately. On applying this theorem many times we get the output from any number of inputs equal to the sum of the outputs from the individual inputs separately.

Question

Given V₁ = 25/0° V and V₂ = 10236.87° V are connected in series. Find the resultant voltage V = V₁ + V2.
(Take cos 36.87° = 0.8, and sin 36.87° = 0.6)
O (17+j31) V
O (6 + j33) V
O (33+j6) V
(33 + j19) V

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