Given two particles with Q = 2.90-uC charges as shown in the figure below and a particle with charge g = 1.37 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = co.) x= -0,800 m x = 0.800 m (a) What is the net force (in N) exerted by the two 2.90-µC charges on the charge q? (Enter the magnitude.) (b) What is the electric field (in N/C) at the origin due to the two 2.90-uC particles? (Enter the magnitude.) |N/C (c) What is the electrical potential (in kV) at the origin due to the two 2.90-µC particles? kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 2.90-µC particles?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 9P: Given two particles with 2.00-C charges as shown in Figure P20.9 and a particle with charge q = 1.28...
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Please solve part d

Given two particles with Q = 2.90-µC charges as shown in the figure below and a particle with charge q = 1.37 x 10 18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = o.)
x = -0.800 m
x = 0.800 m
(a) What is the net force (in N) exerted by the two 2.90-pC charges on the charge q? (Enter the magnitude.)
N
(b) What is the electric field (in N/C) at the origin due to the two 2.90-µC particles? (Enter the magnitude.)
N/C
(c) What is the electrical potential (in kV) at the origin due to the two 2.90-uC particles?
kV
(d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 2.90-pC particles?
Transcribed Image Text:Given two particles with Q = 2.90-µC charges as shown in the figure below and a particle with charge q = 1.37 x 10 18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = o.) x = -0.800 m x = 0.800 m (a) What is the net force (in N) exerted by the two 2.90-pC charges on the charge q? (Enter the magnitude.) N (b) What is the electric field (in N/C) at the origin due to the two 2.90-µC particles? (Enter the magnitude.) N/C (c) What is the electrical potential (in kV) at the origin due to the two 2.90-uC particles? kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 2.90-pC particles?
Three positively charged particles lie along the
x-axis of the x y coordinate plane. O
• Charge a is at the origin.
Charge Q is at (0.800 m,
0).
800 m
Another charge Q is at (-0.800 m,
Transcribed Image Text:Three positively charged particles lie along the x-axis of the x y coordinate plane. O • Charge a is at the origin. Charge Q is at (0.800 m, 0). 800 m Another charge Q is at (-0.800 m,
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