Given this table, find the probability of x les 0 1 2 P(x) 0.50 0.25 0.25 X 0.75 0.25 1 0 0.50

For the probability distribution, find a. X b. P(y> 2) c. F(y= 6) 0.05, 0.10, f(y) = 0.15, 0.20, X, y = -2 y = -1 y = 0 y = 1 y = 2

Answer.

Find the probability P(not E) if P(E)= 0.38. The probability P(hot E) is (Simplify your answer.)

Consider the joint pmf p(x,y) and marginal pmfs p(x) and p(y) for two discrete random variables X and Y as displayed in the table below. X p(x,y) 1 2 3 p(y) 1 0.125 0.0625 0.1875 0.125 0.5 Y 2 0.0625 0.0625 0.125 0.25 0.5 p(x) 0.1875 0.125 0.3125 0.375 1

Find the probability ​P(Ec​) if ​P(E)=0.17.

A certain disease has an incidence rate of 0.2%. The false negative rate is 8%, and the false positive rate is 3%. Calculate the probability that a person who tests positive actually has the disease. 0.0848 Note: The incidence rate is the probability that a random person gets the disease. The false negative rate is the probability of getting a negative result given that the person has the disease. The false positive rate is the probability of getting a positive result given that the person does not have the disease.

Compute the indicated probability. P(A|B)=0.5, P(AnB)=0.4. Find P(B).