Given the initial conditions x(pi/2)=0 and x'(pi/2)=1 Being the ODE: x''+ x = 0 and its family of solution is x = c1 cos t + c2 sin t Find a solution to the Initial Value Problem

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A: topic - trigonometric ratios sin(-x)=-sin(x) cos(-x)=cos(x) sin2(x)+cox2(x)=1