Given the information about the following acids i) HW pka = 2 ii) HX pKa = 10 iii) HY pKa = 12 iv) HZ pKa = 25 Which of these acids react with hydroxide ion (HO) to form water (pka=15.74)? HW, HX, and HY HW and HX only HY and HZ HZ only

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Given the information about the following acids
i) HW pka = 2
ii) HX pKa = 10
iii) HY pKa = 12
iv) HZ pka = 25
Which of these acids react with hydroxide ion (HO) to form water (pka=15.74)?
HW, HX, and HY
HW and HX only
HY and HZ
HZ only
Transcribed Image Text:Given the information about the following acids i) HW pka = 2 ii) HX pKa = 10 iii) HY pKa = 12 iv) HZ pka = 25 Which of these acids react with hydroxide ion (HO) to form water (pka=15.74)? HW, HX, and HY HW and HX only HY and HZ HZ only
Expert Solution
Step 1: ka and pKa of weak acid

Dissociation of a weak acid is given by:

HA space space space rightwards harpoon over leftwards harpoon space space space straight H to the power of plus space space plus space space straight A to the power of minus

he acid dissociation constant of this acid is given by:

straight K subscript straight a space equals space fraction numerator open square brackets straight H to the power of plus close square brackets space open square brackets straight A to the power of minus close square brackets over denominator open square brackets HA close square brackets end fraction

For the strong acid, the value of Ka will be greater than the weak acid. The negative logarithm of the Ka is known as pKa. The pKa of an acid is given by:

pKa = -log Ka

Due to the negative logarithm, the pKa value of a strong acid is less than a weak acid.

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