Given the function f(a,b,c,d)=Em(0,1,2,6,7,8,9,14,15), find the minimum SOP form using a K-Map. Note that there are two solutions for this question. Draw a logic diagram of the minimum SOP form using AND, NOT, and OR gates.
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- An X-input exclusive-OR gate and a Y-input exclusive-OR gate (where X=3, Y=4 have their outputs connected to a 2-input exclusive-NORgate. Do the following:a) Draw the logic diagram and analyze the logic expression of the output (in standard SOPform).b) List out all essential prime implicants.Using full adders in block diagram, other needed logic gates. Show the design of a circuit that performs A – B based on using 2's complement arithmetic where A and B are two unsigned 4-bit numbers. State the condition for error in your design.a) Create a 4 Variable Karnaugh Map in paper by mapping 1’s for given standard SOP Boolean expression. After mapping , make relevant groups within Karnaugh Map by considering rules for making groups for 4 variable Karnaugh Map. After making relevant grouping , extract the minimum SOP expression by considering rules for extracting minimum SOP using Karnaugh Map. * Standard SOP: *Create Circuit Diagram using logic gates and logic converter in Multisim for given standard SOP and minimum SOP which you have solved. Do make sure that truth table for both expressions should evaluate same result.
- Q (A, B, C) = A' .B'. C +A' .B. C + A.B.C' + A.B.C Obtain the simplified function with the Karnaugh Map method in terms of minterms and maxters separately. Set the output functions separately with logic gates with AND NOT for minterms and OR for maxima.Given the following pullup circuit A-Design the pulldown circuitry B- What is the logic function implemented by this would be?Given the function f(a,b,c,d)-IIM(3,4,5,10,11,12,13), find the minimum POS form using a K-Map. Draw a logic diagram of the minimum POS form using AND, NOT, and OR gates. using only NOR gates. Draw a logic diagram for the minimum POS form
- Consider Lookahead Carry Generator circuit . Show how to implement this circuit using minimum number of 4x1 multiplexers and (any number of) inverters (NOT gates). Explain your solution. (you can use logic-1 and logic-0 inputs in your design, if necessary).Which of the following is an important feature of the sum-of-products form of expressions? • The delay times are greatly reduced over other forms. • The maximum number of gates that any signal must pass through is reduced by a factor of two. • No signal must pass through more than 2 gates (not including inverters). • All logic circuits are reduced to nothing more than simple AND and OR gates.Electrical Engineering Task Figure shows a BCD counter that produces a four-bit output representing the BCD code for number of pulses that have been applied to the counter input. In particular, the DCBA outputs will never represent a number greater than 1001,-91, (MOD-10). (MSB) Logic BCD counter circuit HIGH only when DCBA=210-310, or 910 a. Draw the logic circuit using the minimum expression and then explain its operation. B
- Q (A, B, C) = A̅ .B̅. C +A̅ .B. C + A .B. C̅ + A.B.C. Obtain the simplified function with the Karnaugh Map method in terms of minterms and maxters separately. Set the output functions separately with logic gates with AND NOT for minterms and OR for maxima.In this assignment, you are required to design a circuit that counts and displays the sequence of the number 010430011092 . The number will then be displayed on a 7-segment display and changed every 1 second. The block diagram is as shown in Figure 1. Construct your design as follow: - (a) Design a combinational logic circuit that converts binary number to a sequence of the number 010430011092 and to be displayed on a single common anode 7-segment display. The logic circuit must be designed using 2-input NAND gateDesign the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).