Given the following standard reduction potentials: MnO4 (aq) + 8H*(aq) + 5 e - - Mn2*(aq) + 4 H20() E° = 1.51 V Fe3+ (aq) + e Fe<* (aq) E° = 0.77 V What is the cell potential E for the following reaction under the non-standard condition with 0.16 M of MnO4", 0.92 M of Mn2*, 0.96 M of Fe+, and 0.19 M of Fe2* in a buffered solution with 1.0 M of H* ? Please keep your answer to two decimal places. 5FE2* (aq) + MnO4 (aq) + 8H*(aq) (aq) + Mn2+ (aq) + 4H20 () --> 5FE3+

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Chapter1: Chemical Foundations
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Given the following standard reduction potentials:
Mn04 (aq) +
8H*(aq) + 5 e
Mn2*(aq) +
4 H20()
E° = 1,51 V
Fe3+
(aq) + e –
Fe2* (aq)
E° = 0.77 V
What is the cell potential E for the following reaction under the non-standard condition with 0.16 M of MnO4", 0.92 M of Mn2+, 0.96 M of
Fe+, and 0.19 M of Fe2+ in a buffered solution with 1.0 M of H* ? Please keep your answer to two decimal places.
5FE2* (aq) + MnO4 (aq) + 8H*(aq)
5Fe3+ (ag) + Mn2* (aq) + 4H20 ()
-->
Transcribed Image Text:Given the following standard reduction potentials: Mn04 (aq) + 8H*(aq) + 5 e Mn2*(aq) + 4 H20() E° = 1,51 V Fe3+ (aq) + e – Fe2* (aq) E° = 0.77 V What is the cell potential E for the following reaction under the non-standard condition with 0.16 M of MnO4", 0.92 M of Mn2+, 0.96 M of Fe+, and 0.19 M of Fe2+ in a buffered solution with 1.0 M of H* ? Please keep your answer to two decimal places. 5FE2* (aq) + MnO4 (aq) + 8H*(aq) 5Fe3+ (ag) + Mn2* (aq) + 4H20 () -->
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