Given the following equilibrium constants at 427°C: 02(g) + 4Na(I) = 2N220(s) K1 = 2.50×1049 O2(g) + 2Na(I) = 2NAO(g) K2 = 2.50×10° O2(g) + 2Na(I) Na202(s) K3 = 2.00x1028 O2(g) + Na(I) NaO2(s) K4 = 3.33x1013 What would be the value of the equilibrium constant for each of the following reactions, at 427°C? 2Na202(s) = O2(g) + 2N220(s) Submit Answer Tries 0/99 4N2O2(s) = 2N220(s) + 302(g) Submit Answer Tries 0/99

Km.201.

For the reaction:CH4(g) + H2O(g)3H2(g) + CO(g)H° = 206 kJ and S° = 215 J/KThe equilibrium constant, K, would be greater than 1 at temperatures  Kelvin.Select above or below in the first box and enter the temperature in the second box. Assume that H° and S° are constant.

I am doing a calculation wrong somewhere. It keep getting the wrong answer.

The conversion of glucose-6-phosphate to fructose-6-phosphate has a K'eg of 0.5. Based on that information, which of the following sets of changes in the terms of the Gibbs equation is correct? O AH°' negative AS" positive AG negative O AH positive AS' negative AG" positive O AH" positive AS" positive AG" negative O AH' negative AS' positive AG" positive

Please don't provide handwritten solution .....

Calculate E°cell in V for a reaction with K. = 6.99 x 10-15 and n = 4. Your Answer: Answer units

Determine the value of AG for the reaction at 309 K. Assume standard concentration 2NH;(g) = N,H,(g) + H, (g) Given AH (kJ/mol) S°J/{mol · K)) Substance NH3(3) -46.1 192.5 95.35 N2H4(g) H2(3) 238.5 0.0 130.6 O-87.0 kJ -182.5 kJ O -192.6 kJ O 87.0 kJ O 192.6 kJ

< ✓ 11 Question 25 of 25 (1 point) | Question Attempt: 1 of 2 ✓ 12 ✓ 13 ✓ 14 Here are some facts about the reaction: ✓ 15 At -5.67 °C the concentration equilibrium constant K = 7.0 for a certain reaction. с • If the reaction is run at constant pressure, 101. kJ/mol of heat are absorbed. X 16 -1 1 • The constant pressure molar heat capacity C₂ = 2.23 J-mol K Р Using these facts, can you calculate Kat 9.4 °C? • If the reaction is run at constant pressure, the volume increases by 13.%. If you said yes, then enter your answer at right. Round it to 2 significant digits. If you said no, can you at least decide whether Kat 9.4 °C will be bigger or smaller than Kat -5.67 °C? O Yes. O No. 0 17 Yes, and K will be bigger. No. Yes, and K will be smaller.

[Rev Topics] [References] Use the References to access important values if needed for this question. Consider the following reaction where Ke = 6.30 at 723 K. 2NH3 (9) N₂(g) + 3H₂(g) A reaction mixture was found to contain 0.000687 moles of NH3(g), 0.0258 moles of N₂ (g), and 0.0435 moles of H₂(g), in a 1.00 liter container. Calculate Qc. Qc = 1 Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? The reaction must run in the forward direction to reach equilibrium. The reaction must run in the reverse direction to reach equilibrium. The reaction is at equilibrium. Submit Answer Retry Entire Group 9 more group attempts remaining Previous Next> ad Exit ? or n er