Given the following data in measuring a distance of a certain line:   Distance No. of Measurements 740.53 4 740.59 3 740.57 6 740.53 7   Determine the most probable value of the measurements.

A line is laid out using a 50-m tape. The standard error of each tape length laid out is assumed to be ±0.03. If a total length of 2400 m is laid out, what is the standard error of the length of the line? A. ±0.028 C. ±1.440 B. ±0.009 D. ±0.208 Determine the correct length of a line, 256.32 m long, measured using a 50 m steel tape at 38 °C. The steel tape was calibrated at 20 °C. A 256.310 C. 256.374 B. 256.266 D. 256.330 ps. with solution, please.

The % error, or E5o = 0.6745(0), is the so called probable error. It establishes limits which the %3D observations should fall half of the time. O 50 O 68 O 95 O 90

How to solve for the Taped Distance and Percentage of Error? Show your step-by-step solution.

50 28 00 30 us o0 uS 1300 60 u2 00 25 30 00 18 40 00 for the fiqure Shown Calculate the Circular andd abbreviatec divection of of all the lines of the polygon

Azimuth Azimuth Fraction) Length Degrees Minutes Seconds Line 10047 86.99 100 28 AB 44 186.18 186 10 BC 259 89 0.00 CD 100.11 125.32 115 12 44 115.21 DE 323 10 323.17 EA 284.548 SUM 856.858 7. Determine the FGCC dassification of the angle measurements in the problem shown here. Interior Angles Degrees Minutes Seconds 80 28 86 10 44 100 01 215 12 4. 58 3. 18 SUM 69

applying rounding and significant figures rules

What will be the value of total co- ordinate of B, if it is initially assumed as 100 and N latitude at A is given as ?192.96 229.69 O 292.96 O 929.69 92.96 O 29.69 O

Tabulate observed and computed values accordingly. Trial Line Length (m) Difference Мean Relative Precision 1 AB 258.50 ВА 258.85

The most probable value of several measurements of a line is 546.75 m. If 0.15 represents the probable error of the mean value, the changes are event that the true value Lies between 546.60 m and 546.90 m, as it is also probable that the true value lies outside of these limiting values O b. Lies between 546.75 m and 546.90 m, as it is also probable that the true value lies outside of these limiting values Oc. Is equal to 546.90 m Od. Is equal to 546.60 m