Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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### Question 1

**Diagram Explanation:**
The image shows an electrochemical cell setup. It consists of two half-cells connected by a salt bridge and joined to a voltmeter. The left half-cell has magnesium (Mg) immersed in a solution of magnesium nitrate \((\text{Mg(NO}_3)_2)\), and the right half-cell contains silver (Ag) in a silver nitrate \((\text{AgNO}_3)\) solution.

#### Questions:

1. **Given the electrochemical cell in the picture:**

   a. **In the balanced cell reaction, the number of electrons transferred is** [Select]

   b. **The electrons would flow** [Select]

   c. **The standard (assuming 1 M concentrations) cell potential is** [Select]

   d. **The change in standard Gibbs' Energy, \(\Delta G\), for the overall reaction would be** [Select]

   e. **The [Select]**

   f. **If the voltmeter is replaced with a resistor (that allows current to flow) and the current is measured to be a constant 1.250 A, it would take** [Select]

   g. **If the concentrations were changed to \([\text{Mg}^{2+}] = 5.00 \, \text{M}\) and \([\text{Ag}^+] = 0.0100 \, \text{M}\), the cell potential would then be** [Select]

#### Diagram Details:

- **Components:**
  - **Voltmeter:** Measures the potential difference between the two electrodes.
  - **Salt Bridge:** Maintains electrical neutrality by allowing the movement of ions between the two solutions.
  - **Electrodes:** Mg on the left, Ag on the right.

- **Half-Cell Reactions:**
  - **Anode (Mg):** Mg(s) → Mg\(^{2+}\)(aq) + 2e\(^{-}\)
  - **Cathode (Ag):** Ag\(^{+}\)(aq) + e\(^{-}\) → Ag(s)

The queries relate to the understanding of electrochemical cell operations and various calculations like determining the cell potential, Gibbs' free energy change, and effects of changes in concentration on the cell's potential.
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Transcribed Image Text:### Question 1 **Diagram Explanation:** The image shows an electrochemical cell setup. It consists of two half-cells connected by a salt bridge and joined to a voltmeter. The left half-cell has magnesium (Mg) immersed in a solution of magnesium nitrate \((\text{Mg(NO}_3)_2)\), and the right half-cell contains silver (Ag) in a silver nitrate \((\text{AgNO}_3)\) solution. #### Questions: 1. **Given the electrochemical cell in the picture:** a. **In the balanced cell reaction, the number of electrons transferred is** [Select] b. **The electrons would flow** [Select] c. **The standard (assuming 1 M concentrations) cell potential is** [Select] d. **The change in standard Gibbs' Energy, \(\Delta G\), for the overall reaction would be** [Select] e. **The [Select]** f. **If the voltmeter is replaced with a resistor (that allows current to flow) and the current is measured to be a constant 1.250 A, it would take** [Select] g. **If the concentrations were changed to \([\text{Mg}^{2+}] = 5.00 \, \text{M}\) and \([\text{Ag}^+] = 0.0100 \, \text{M}\), the cell potential would then be** [Select] #### Diagram Details: - **Components:** - **Voltmeter:** Measures the potential difference between the two electrodes. - **Salt Bridge:** Maintains electrical neutrality by allowing the movement of ions between the two solutions. - **Electrodes:** Mg on the left, Ag on the right. - **Half-Cell Reactions:** - **Anode (Mg):** Mg(s) → Mg\(^{2+}\)(aq) + 2e\(^{-}\) - **Cathode (Ag):** Ag\(^{+}\)(aq) + e\(^{-}\) → Ag(s) The queries relate to the understanding of electrochemical cell operations and various calculations like determining the cell potential, Gibbs' free energy change, and effects of changes in concentration on the cell's potential.
**Question 1**

The image shows a diagram of an electrochemical cell with the following components:

- **Voltmeter:** Connected to measure the potential difference across the cell.
- **Salt Bridge:** Allows the flow of ions to maintain charge balance.
- **Electrodes:** Magnesium (Mg) and Silver (Ag).

### Electrochemical Cell Description:

- **Left Side:**
  - **Electrode:** Magnesium (Mg)
  - **Solution:** Magnesium Nitrate (\(\text{Mg(NO}_3\text{)}_2\))

- **Right Side:**
  - **Electrode:** Silver (Ag)
  - **Solution:** Silver Nitrate (\(\text{AgNO}_3\))

### Questions and Options:

1. **Given the electrochemical cell in the picture:**

   - **In the balanced cell reaction, the number of electrons transferred is:**
     - [Select]

   - **The electrons would flow:**
     - [Select]

   - **The standard (assuming 1 M concentrations) cell potential is:**
     - [Select]

   - **The change in standard Gibbs' Energy, \(\Delta G\), for the overall reaction would be:**
     - [Select]

2. **Statements with checkbox options:**

   - Silver electrode gains mass because the silver is oxidized.
   - Magnesium electrode gains mass because the magnesium is oxidized.
   - Magnesium electrode gains mass because the magnesium ions are reduced.
   - Silver electrode gains mass because the silver ions are reduced.

3. **Calculation Questions:**

   - If a current is measured to be a constant 1.250 A, it would take [Select] time for a specific change.

   - If the concentrations were changed to \([\text{Mg}^{2+}]=5.00 \text{M and } [\text{Ag}^+]=0.0100 \text{M}\), the cell potential would be:
     - [Select]

**Question 2**

[Not shown in the image.]
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Transcribed Image Text:**Question 1** The image shows a diagram of an electrochemical cell with the following components: - **Voltmeter:** Connected to measure the potential difference across the cell. - **Salt Bridge:** Allows the flow of ions to maintain charge balance. - **Electrodes:** Magnesium (Mg) and Silver (Ag). ### Electrochemical Cell Description: - **Left Side:** - **Electrode:** Magnesium (Mg) - **Solution:** Magnesium Nitrate (\(\text{Mg(NO}_3\text{)}_2\)) - **Right Side:** - **Electrode:** Silver (Ag) - **Solution:** Silver Nitrate (\(\text{AgNO}_3\)) ### Questions and Options: 1. **Given the electrochemical cell in the picture:** - **In the balanced cell reaction, the number of electrons transferred is:** - [Select] - **The electrons would flow:** - [Select] - **The standard (assuming 1 M concentrations) cell potential is:** - [Select] - **The change in standard Gibbs' Energy, \(\Delta G\), for the overall reaction would be:** - [Select] 2. **Statements with checkbox options:** - Silver electrode gains mass because the silver is oxidized. - Magnesium electrode gains mass because the magnesium is oxidized. - Magnesium electrode gains mass because the magnesium ions are reduced. - Silver electrode gains mass because the silver ions are reduced. 3. **Calculation Questions:** - If a current is measured to be a constant 1.250 A, it would take [Select] time for a specific change. - If the concentrations were changed to \([\text{Mg}^{2+}]=5.00 \text{M and } [\text{Ag}^+]=0.0100 \text{M}\), the cell potential would be: - [Select] **Question 2** [Not shown in the image.]
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