Given the diagram below, determine the following: 3 m 2 m 2m Im im-1.5m. 1.5m 15m 3 kN 3.m 2m 4 kN A. Vector form of position vector CB (in m). B. Vector form of position vector DA (in m). C. Magnitude of the moment (in kN-m) due to the 3kN force about point D. D. Magnitude of the moment (in kN-m) due to the 4kN force about point C.

F1 F2 F3 A b F4 D F5 Consider the following values: - a = 25 m; b 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 5 kN; F3 = 6 kN; F4 = 7 kN; F5 = 8 kN; a = 30°, 0 = 60° %3D B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 75.8 kN.m b) 32.7 kN.m c) - 14.6 kN.m d) 72.9 kN.m e) 27.1 kN.m - 66.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) - 198.8 kN.m b) 212.7 kN.m c) - 121.6 kN.m d) 98.9 kN.m e) 125.4 kN.m f) -170.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 96.7 kN.m b) 251.1 kN.m c) - 114.6 kN.m d) 217.9 kN.m 154.1 kN.m f)-177.7 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 198 kN.m b) 127 kN.m c) – 219 kN.m d) 369 kN.m e) 151 kN.m f) - 171 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting

Problem 4.39 Consider the system shown in (Figure 1). Figure 70 F-80 lb 8 CISA 16 15 58 1 of 1 Part A Determine the moment of the force F about the door hinge at B. Express the result as components of a Cartesian vector. Enter the x, y, and components of the moment in pound-feet to three significant figures and separated by commas. (Ms),.(Ms), (Ms) = Submit Provide Feedback Request Answer 195| ΑΣΦ. 241 | vec A A C ? lb-ft

4) Determine the total moment caused by the forces Fp4 and Fca about the plate diagonal that goes through point B (the dashed line). Write your answer in cartesian vector notation. FCA= 500 lb 14 ft FRA = 350 Ib FDA= 400 lb 3 ft-> 3 ft 3 ft 2 t 6 ft

Untitled Section F1 F2 a F3 d F4 Consider the following values: - F5 a = 16 m; b = 11 m; c = 13 m; d = 8 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30° , 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 88.8 kN.m b) 76.3 kN.m c) 19.6 kN.m d) 55.5 kN.m e) 59.1 kN.m f) 81.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 88.8 kN.m b) 120.8 kN.m c) 31.6 kN.m d) 98.9 kN.m e) 41.1 kN.m f) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 125.7 kN.m b) 178.1 kN.m c) 254.6 kN.m d) 439.1 kN.m e) 144.1 kN.m f) 215.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 77.8 kN.m b) 98.3 kN.m c) 100.6 kN.m d) 18.9 kN.m e) 97.1 kN.m f) 60.1 kN.m 5] What is the moment of the force F2 about point E? Activate V ) 151.3 kN.m Go to Setting! a) 122.7 kN.m b) 108.1 kN.m c) 66.6 kN.m d) 83.1 kN.m e)…

The system shown has, F,-231 lbf, F,-172 lbf, M-703 ft-lbs, 0-51, a-1.9ft, b-5.3ft, and e- 3.2ft. f. If the force, F,, is moved to point A, what moment needs to be added to create an equivalent system? a A M e b g. If the moment, M, is moved to point A, what moment needs to be added to create an equivalent system? h. If the force, F2, is moved to point A, what moment needs to be added to create an equivalent system? F

F1 F2 a F3 A d b C F4 E Consider the following values: - F5 a = 12 m; b = 10 m; c = 10 m; d = 8 m; F1 = 6 kN; F2 = 7 kN; F3 = 8 kN; F4 = 9 kN; F5 = 10 kN; a = 30° , 0 = 45° ß = 60° 4] What is the resultant moment of the five forces acting on the rod ut point D? 51 What is the moment of the force F2 about point E? 6] What is the resultant moment of the five forces acting on the rod about point E?

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F2 F3 F4 Consider the following values: - F5 a = 25 m; b = 5 n; a = 25 m; d = 5 m; F1 - 6 kN; F2 - 7 kN; F3 - 8 kN; P4 - 9 kN; PS - 10 kN; a- 45. 0-60 , - 30 1) What is the resultant moment of the five forces acting on the rod about point A? a)- S8S KNm b) 12.7AN.m 9-7.1 KNm 029AN.m ) 24.1 KN.m 0-47.1 AN.m 2) What is the resultant moment of the five forces acting on the rod about point B? a) 108 LNm 9- 191 KN.m ) 124 AN.m b) 227 AN. 4) 155 LN.am 9242 N. 3) What is the resultant moment of the five forces acting on the rod about point C? 0 35.3 KN.m )- 9.7 KN.m b) 151.I KNm 0-2088 KN.m )2179 KN.m )-1741 KN.am 4] What is the resultant moment of the five forces acting on the rod about point D? )- 217.5 AN. b) 182.7 AN )- 198.5 KN.m 4) 136.9 kN.m ) - 287.1 kN. H 310.1 ka 5] What is the moment of the force F2 about point E? a) 111.7 KN.m b) 218.1I KN.m ) 138.7 KN.m d) 193.1 KN.m e) 101.1 KN.m 0 321.3 KN.m

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