Given the array BWT[1:n], write the pseudocode to compute the array rank[1:n] in O(n ) time, assuming that the alphabet size is constant. 2. Given the arrays BWT[1:n] and rank[1:n], write pseudocode to compute T' in O(n) time Please provide detailed explanation.
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![Given the array BWT[1:n], write the pseudocode to compute the array rank[1:n] in O(n
) time, assuming that the alphabet size is constant. 2. Given the arrays BWT[1:n] and
rank[1:n], write pseudocode to compute T' in O(n) time Please provide detailed
explanation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7382f5bd-6369-4911-8b1a-2abf92efa5bd%2F76201bcc-e948-4809-8069-95f9f54369e9%2Fh2zbwt4_processed.png&w=3840&q=75)
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- Given the following 1D array of 7 strings: "MILK" "TEETH" The first element located at index 0 is "MILK". The last element located at index 6 is "APPLE". (Note that the indexing starts from 0) "HORSE" "YOYO" 1. Right after the first iteration, the element at index 6 is: Fill in the blanks below: 2. Right after the second iteration, the element at index 1 is: Perform Selection Sort to rearrange the elements in alphabetical order. Simulate the algorithm and fill in the required array element values in the following items. You have the option not to to type the double quotes in your answers. Use ALL CAPS when entering the text. 3. Right after the third iteration, the element at index 6 is: "ROBOT" 4. Right after the fourth iteration, the element at index 3 is: "QUEEN" "APPLE" MILKpython porogram - Let G be an array from -2. to 3.*pi in 10,000 steps. Write the syntax for finding the index where G == -pi/3.Q: Write a program / Pseudo code / Algorithm that inserts the following numbers into two Separate arrays. L1 à 50 30 25 75 82 28 77 L2 à 50 40 25 75 80 21 37 30 After Insertion median should be calculated for each adjacent element from both array structures, after computing median print / Output that array M. if M is the median them M0 = (L1[0]+L2[0]) /2 M1 = (L1[1]+L2[1]) /2 …………..
- This code segment generate an array 5-by-5 showing that each element in the upper triangle is equal to 0, each element in the diagonal is equal to 1, and each element in the lower triangle is equal to 5. For I 1 To 5 For j = 1 To 5 1-....... 2-.. 3-.. 4-.. 5-. 6-.... End If Next j Next I O 1-If I j 6-A(I, j) = 1 1-If I j Then 2-A(1, j) = 0 3-Else if IAlgorithm Design & Analysis You are given an array called source, with length n, and a set of m arrays called target, each also with length n. The arrays contain only positive integers. The arrays are unsorted. For any number x, the smallest number in target[x] is guaranteed to be smaller than target[x+1]. All the numbers in target are unique. The following figure illustrates an example of valid source and target arrays for this case, where n=5 and m=6. The smallest number in each array in target is styled with bold and italic. You can quickly see that the smallest number in target[0] is smaller than the smallest number in target[1], the smallest number in target[1] is smaller than the smallest number in target[2], and so on. You can also see that there is no duplicate number within the arrays in target. You are asked to design an algorithm to find if there is an array in b that has the same set of numbers as in a. In the above case, your algorithm should return true, because…You have two 1d arrays A [20] & B [20], fill them randomly with 20 - 100 numbers for array A [20] set odd rows to zero And for array B [20] set even rows to zero then combine the two arrays in array C [20] and find the maximum numberCreate an array called QArray of 100 elements of type integer. Then fill the array with the odd values 1, 3, 5, 7, .…. (b) Calculate the print the summation of all elements in this array. (c) calculate and print the average of all array elementsWhich is the Numpy function to calculate the standard deviation on the following array: a=np.array([1,2,3,4,5]) a. np.std(a) Ob. a=np.array([1,2,3,4,5]) O. np.median(a) O d. np.average(a)1. Write an algorithm that applies right shift on one dimensional array (trace your algorithm on example array A: [0, 9, 2, 10, 3] and show the result of your trace steps as a table). *Dont use extra array while solving this problem *Just write algorithm do not write program in any other programming languageWrite a function definition to compute and print the deviation of every array value from the mean.This function should do the following:1. Compute the mean (average value) of the array.2. For each array element, print the difference between the value and the mean. Difference should be a positive value (absolute value).ExampleGiven the array 38 11 23 39 34 with an average value of 29 print:9 18 6 10 5 atom code only, no other software codes pleaseMulti Dimensional Arrays in C Program Ask the user for the number of rows and columns of a two-dimensional array and then its integer elements. Then, ask the user for another integer value which represents a boogeyman. A boogeyman is a value that we intend to find from a given array. Find and output the coordinates of the boogeyman by this format: "BOOGEYMAN LOCATED AT ROW {row_number}, COLUMN {column_number}!" Input 1. One line containing an integer for the number of rows 2. One line containing an integer for the number of columns 3. Multiple lines containing at least one integer each line for the elements of the array Sample 1 4 2 3 9 1 2 3 4 2 1 1 9 2 8 3 4. One line containing an integer for the boogeyman's value Output Print the row of the position first and then the column of the position. Note that the row and the column is 0-based (i.e. it starts at 0 and not at 1). It is guaranteed that the boogeyman exists and only once in the 2D array. Enter# of rows: 4 Enter…#using python # This method will check the given array across the base array and if they are equivalent interms of values return true, or else return false def equivalent(self, cir_arr): # To Do print("==========Test 9==========") lin_arr8 = [10, 20, 30, 40, 50, 60, None, None, None] c9 = CircularArray(lin_arr8, 8, 6) c6.printForward() # This should print: 10, 20, -30, 20, 50, 30 c9.printForward() # This should print: 10, 20, 30, 40, 50, 60 print(c6.equivalent(c9)) # This should print: FalseSEE MORE QUESTIONS