Given the allocated address regions in the memory layout of 32-bit MIPS, what is the size, in bytes, of the user's text segment? How many instructions can the largest user program have and still fit? O a. 192 MB, roughly 50 million instructions O b. 192 MB, roughly 200 million instructions 256 MB, roughly 67 million instructions 256 MB, roughly 268 million instructions C. O d. O e. 64 MB, roughly 67 million instructions O f. 64 MB, roughly 17 million instructions
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- If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?Suppose the RAM for a certain computer has 4M words, where each word is 16 bits long. What is the capacity of this memory expressed in bytes? If this RAM is byte addressable, how many bits must an address contain? If this RAM is word addressable, how many bits must an address contain?A microprocessor has a 32-bit address line. The size of the memory contents of each address is 8 bits. The memory space is defined as the collection of memory position the processor can address. What is the address range (lowest to highest, in hexadecimal) of the memory space for this microprocessor? What is the size (in bytes, KB, or MB) of the memory space? 1 KB = 21010 bytes, 1MB = 22020 bytes, 1GB = 23030 bytes A memory device is connected to the microprocessor. Base o the size of the memory, the microprocessor has assigned the addresses 0xA4000000 to 0xA07FFFFF to this memory device. What is the size (in bytes, KB, or MB) of this memory device? What is the minimum number of bits required to represent the addresses only for this memory device?
- Suppose the RAM for a certain computer has 256M words, where each word is 16 bits long. a. What is the capacity of this memory expressed in bytes? b. If this RAM is byte addressable, how many bits must an address contain? c. If this RAM is word addressable, how many bits must an address contain?Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a cache of 128 blocks, where each cache block contains 64 bytes.Q.) What is the format of a memory address as seen by the cache; that is, what are the sizes of the tag and offset fields?Given a computer equipped with 536,870,912 bytes of memory with 16-bit cells, how many bits are needed to specify a memory address?
- Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a cache size of 512 bytes, and each cache block contains 64 bytes.Q.) What is the format of a memory address as seen by cache; that is, what are the sizes of the tag, block, and offset fields?Suppose a computer using fully associative cache has 224 words of main memory and a cache of 512 blocks, where each cache block contains 16 words. What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag, block, and offset fields?Suppose a computer using direct mapped cache has 2^32 bytes of byte-addressable main memory and a cache size of 512 bytes, and each cache block contains 64 bytes. a. How many blocks of main memory are there? b. What is the format of a memory address as seen by cache, i.e., what are the sizes of the tag, block, and offset fields?
- Suppose we have a byte-addressable computer using fully associative mapping with 16-bit main memory addresses and 32 blocks of cache. Supposed also that each block contains 16 bytes. The size of the offset field is 19 bits and the size of the block field is 0.625 bytes.In a 64-bit machine, with 2 GB RAM, and 8 KB page size, how many entries will be there in the page table if it is inverted?What is the difference between bit address 7CH and byte address 7CH? What is the specific location of bit address 7CH in memory?