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Given that the acceleration vector is a(t) = (−9 cos(3t))i + (−9 sin(3t))j + (3t)k, the initial velocity is v(0) = i + k, and the initial position vector is r(0)=i+j+k, compute: A. The velocity vector v(t) B. The position vector r(t) = 1+ 3 sin(-3f) i+ t+cos(-3t) i+ j+1+ 31/232 k j+1+1+ +1+2 | * k

Given that the acceleration vector is a(t) = (−9 cos(3t))i + (−9 sin(3t))j + (3t)k, the initial velocity is v(0) = i + k, and the initial position vector is r(0)=i+j+k, compute: A. The velocity vector v(t) B. The position vector r(t) = 1+ 3 sin(-3f) i+ t+cos(-3t) i+ j+1+ 31/232 k j+1+1+ +1+2 | * k

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Given that the acceleration vector is a(t) = (−9 cos(3t))i + (−9 sin(3t))j + (3t)k, the initial velocity is v(0) = i + k, and the initial position vector is r(0)=i+j+k, compute: A. The velocity vector v(t) B. The position vector r(t) 1+ 3 sin(-3t) i+ j+1+ t+cos(-3t) i+ 3t k j+1+t+ +2k
Transcribed Image Text:Given that the acceleration vector is a(t) = (−9 cos(3t))i + (−9 sin(3t))j + (3t)k, the initial velocity is v(0) = i + k, and the initial position vector is r(0)=i+j+k, compute: A. The velocity vector v(t) B. The position vector r(t) 1+ 3 sin(-3t) i+ j+1+ t+cos(-3t) i+ 3t k j+1+t+ +2k
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