Given that n=5, find the phasor voltage and current V1, V2, I1, and I2.
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Given that n=5, find the phasor voltage and current V1, V2, I1, and I2.
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1: n :
+
100-j75
120°V
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- Determine ZT for the circuit if inductive reactive is 10220 and resistance is 9850. Answer:Draw the waveform of voltage and current under the following conditions: A current which lags the voltage by 60°. A current which leads the voltage by 60°. A current which is in phase with the voltagegoogle.com/forms/d/e/1FAlpQLScF2Wzu92iVI-tEM2nxdhqXrGdR460G4QCTxaUZZeC678PqTg/formResponse مطلوب /06 *:The potential at point P due to Q1 and Q2 is Q, = 1x10-12C 0.5 m 0.5 m Qz = 1x10-12C %3D 50 cm 0.01797 V Ov O -0.01271 V O 0.01271 V O Insert PIC F10 F11 F12 F6 F7 FB Backspace 9 € P Enter H
- A generator rated at 30MVA, 11kV has a reactance of 40%. Calculate its p.u. reactances for a base of 50MVA and 10kV. O 0.606 p.u. O 0.506 p.u. O 0.806 p.u. O 0.706 p.u.Ererrises: IA platinum oil has a resifance of 3-14k r at go°C and 3.747JV at 100°C.- Fin'd the resistance at o'C ond the kmp -creff. of resifonce af 40°C 2. A pofential difference of r5oV is apphed to a field wnding at 15°C and the currend is SA. What will be the mean fempouafure of the winiding when currend has falen to 3.91A, apphedvrltage being constant Aasume s =p7.5. 3. A cril has a resi fance of 182 when its mean femperature is 20°C and 20v when ik mean femperature s 50°C. Frid is mean femperature rise when ik resotonce is 21JL and the sorrandinig femperature is i5°C. A cril of a relay takes a curre of 0.12 A when it is at the vem insbi o al 4. A jemperature of is'C ond canneckerdacms a oV supply If the minimum operating current of the relay is 0.1 A, colculate the femperature above ohich the relay will fail to operate when connected ti the same supply. Resi tncenfemp.coefficrenf of the cril makria] is o.0043 per °C at 0°C.Let's say you measure t1/2 to be 0.037 seconds and the resistance in the circuit is 68 Ohms. Then what is the capacitance in micro Farads? Answer in micro Farads.
- Solution plzplease answer asapp tyShown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Determine the numerical value of Ztot = 2890.5 Determine the numerical value of $z= = 41 Determine the current through the circuit: • I(PEAK) = 4.81E-3 • I(RMS) = 3.404E-3 Determine the voltage across the resistor: • VR(PEAK) = 7.387 • VR(RMS) = 5.22 ✔✔ Amps ✔Amps Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701 R x Volts X Volts Determine the voltage across the inductor: • VL(PEAK) = 9.184 • VL(RMS) = 6.49 ✔ Volts Volts L R²+ WL- ✔ degrees 2 If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher…
- QUESTION 3 An inductor, a capacitor, and a resistor are connected in parallel with a function generator. The inductor draws 100mA RMS, the capacitor draws 150mA RMS, and the resistor draws 200mA RMS. Find the magnitude of the total current. O 450mA RMS O 544mA RMS O 352mA RMS O 206mA RMSIn the figure: R1 = 1439.170, R2 = R1 and R3 =2R2, then determine the value of the voltage source E. a 8 mA 10 mA 2 mA RT R1 R2 R3 O 25.33 11.51 O 17.27 15.43 13.82 +From step1, how did you get that 50+(80*j60/80+j60) = 78.8+j38.4? also in step 2, how did you get that 5/(0.0125-0.0167) = 143.63 + j191.89?
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