Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Question
Given ArrayList<String> mascots ("lion", "eagle", "badger", "snake"), what is output?
for (int i = 0; i < mascots.size() - 1; ++i) {
System.out.print(mascots.get(i) + " ");
}
Group of answer choices
A)0 1 2 3
B)lion eagle badger
C)0 1 2
D)lion eagle badger snake
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- In C++, write a program that reads in an array of type int. You may assume that there are fewer than 20 entries in the array. The output must be a two-column list. The first column is a list of the distinct array elements and the second column is the count of the number of occurences of each element.arrow_forwardPROBLEM STATEMENT: In this problem you will need to insert 5 at the frontof the provided ArrayList and return the list. import java.util.ArrayList;public class InsertElementArrayList{public static ArrayList<Integer> solution(ArrayList<Integer> list){// ↓↓↓↓ your code goes here ↓↓↓↓return new ArrayList<>(); Can you help me with this question The Language is Javaarrow_forwardFor any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20,30, 1 #include 2 3 int main(void) { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; 4 6 7 8 scanf("%d", &keysList[0]); scanf ("%d", &keysList[1]); scanf("%d", &keysList[2]); scanf("%d", &keysList[3]); 10 11 12 13 scanf ("%d", &itemsList[0]); scanf ("%d", &itemsList[1]); scanf("%d", &itemsList[2]); scanf ("%d", &itemsList[3]); 14 15 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }arrow_forward
- What’s the output?arrow_forwardIntegers numberOfParts, required Groups, and invalid Groups are read from input. If numberOfParts is 21 or more, then add 3 to requiredGroups. Otherwise, add 6 to invalidGroups. ► Click here for examples 3 public class GroupSurvey { 4 public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int numberOfParts; int requiredGroups; I int invalidGroups; 345679 8 9 10 11 12 13 14 15 16 17 18 19 20 } numberOfParts = scnr.nextInt (); requiredGroups = scnr.nextInt (); invalidGroups = scnr.nextInt (); /* Your code goes here */ if(numberOfParts>21){ requiredGroups= System.out.println(requiredGroups); System.out.println(invalidGroups);arrow_forwardpublic class arrayOutput ( public static void main (String [] args) { final int NUM ELEMENTS = 3; int[] userVals = new int [NUM_ELEMENTS]; int i; } Type the program's output userVals [0] = 2; userVals [1] = 6; userVals [2] = 8; for (i = userVals.length - 1; i >= 0; −−1) { System.out.println(userVals [1]); } C.C. ? ? ??arrow_forward
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