Given an actual demand this period of 103, a forecast value for this period of 99, and an alpha of .4, what is the exponential smoothing forecast for next period? Forecast [Blank1] O 94.6 O 103.0 O 100.6 O 97.4

8.6 Using exponential smoothing, calculate the forecasts for months 2, 3, 4, 5, and 6. The smoothing constant is 0.2, and the old forecast for month 1 is 245. Month 1 2 3 4 5 6 LO Actual Demand 260 230 225 245 250 Forecast Demand

Assume Sandra's forecasted ADR for the night is $1600.99. What would be her estimated total room revenue for this day? ADR = Total room revenue / Number of rooms sold

Given an actual demand this period of 90, a forecast for this period of 58, and an alpha of 0.2, what would the forecast for the next period be using exponential smoothing?

(4) Exponential smoothing with a smoothing constant equal to 0.15, assuming a March forecast of 15(000). (Round your intermediate forecast values and final answer to 2 decimal places.) Forecast thousands (5) A linear trend equation. (Round your intermediate calculations and final answer to 2 decimal places.) Yt thousands

Use simple exponential smoothing with a=0.6 to forecast chargers sales for February through May. Assume that the forecast for January was 24 chargers. *** Month January Charger Sales 42 February 33 March 28 April 59 May ? a) What will be the forecast for May? b) Calculate the MSE.

Using exponential smoothing with alpha = .2, and assuming the forecast for period 11 was 80, what would the forecast for period 14 be?

Forecast error is calculated as: Actual - Forecast O Forecast - Actual (Forecast - Actual) ^ 2 Absolute (Actual - Forecast) (Actual - Forecast) ^ 2

Respond to each of the items using the following time series data. Period Demand 144 2 172 3 157 4 160 144 181 7 160 8 176 9. 149 10 183 11 182 12 149 13 153 14 164 15 153 16 104 Click here for the Excel Data File b. Compute all possible forecasts using a five-period moving average. (Round your answers to 1 decimal place.) Absolute Period Demand 5-period SMA Errors 1 144 172 3 157 4. 160 5 144 181 7 160 8 176 9 149 10 183 11 182 12 149 13 153 14 164 LO

d) Using exponential smoothing with α ​= 0.40 and the forecast for year 1 being 3,000​, the forecast for year 6​ = ? miles ​(round your response to the nearest whole​ number).