LAB RESTRICTIONS, PLEASE READ:
- Do not add any imports, the ones that you need will be given to you.
- Do not use recursion.
- Do not use try-except statements, you should be able to anticipate
or prevent any errors from happening at all!
- Code in python
- Should work for given doctest
def longest_unique_substring(s: str) -> str:
"""
Given a string <s>, return the longest unique substring that occurs within
<s>.
A unique substring is a substring within <s> which DOES NOT have any
repeating characters. As an example, "xd" is unique but "xxd" is not.
If there are two equal length unique substrings within <s>, return the one
that starts first (i.e., begins at a smaller index).
>>> longest_unique_substring('aab')
'ab'
"""
Step by stepSolved in 4 steps with 2 images
- // MichiganCities.cpp - This program prints a message for invalid cities in Michigan. // Input: Interactive // Output: Error message or nothing #include <iostream> #include <string> using namespace std; int main() { // Declare variables string inCity; // name of city to look up in array const int NUM_CITIES = 10; // Initialized array of cities string citiesInMichigan[] = {"Acme", "Albion", "Detroit", "Watervliet", "Coloma", "Saginaw", "Richland", "Glenn", "Midland", "Brooklyn"}; bool foundIt = false; // Flag variable int x; // Loop control variable // Get user input cout << "Enter name of city: "; cin >> inCity; // Write your loop here // Write your test statement here to see if there is // a match. Set the flag to true if city is found. // Test to see if city was not found to determine if // "Not a city in Michigan" message should be printed.…arrow_forward+ dgenuity.com/Player/ Semester A def fib(n): Complete the code for this recursive function. if n == 1: return 0 if n == 2: return 1 else: 3 return 5 # The first number in the list. # The second number in the list. # Add the previous two numbers. Mark this and return (n-1) + O (n-2) Σ B 0 Save and Exit Next Sign out English Martarrow_forwardc++arrow_forward
- SYNTAX ERROR HELP - PYTHON This also happens for several other 'return result' lines in the code. import randomdef rollDice(): num1 = random.randint(1, 6) num2 = random.randint(1, 6) return num1, num2def determine_win_or_lose(num1, num2): result = -1 total = num1 + num2print(f"You rolled {num1} + {num2} = {total}")if total == 2 or total == 3 or total == 12: result = 0elif total == 7 or total == 11: result = 1else: print(f"point is {total}") x = determinePointValueResult(total)if x == 1: result = 1else: result = 0 return resultdef determinePointValueResult(pointValue): total = 0 result = -1while total != 7 and total != pointValue: num1, num2 = rollDice() total = num1 + num2if total == pointValue: result = 1elif total == 7: result = 0print(f"You rolled {num1} + {num2} = {total}")return resultwhile i < n: num1, num2 = rollDice() result = determine_win_or_lose(num1, num2)if result == 1: winCounter += 1 print("You…arrow_forward- Do not add any imports, the ones that you need will be given to you.- Do not use recursion.- Do not use break/continue.- Do not use try-except statements, you should be able to anticipateor prevent any errors from happening at all!arrow_forwardint main(){ string str; int count = 0; // user input cout << "Enter string: "; cin >> str; int n = str.length(); // iterating over the string for (int i = 0; i < n - 1; i++) { // calling the fucntion to find the palidrome strings from the user input if (isPalindrome(0, i, str) && isPalindrome(i + 1, n - 1, str)) { // if 2 substring are palindrome then print them and increment count for (int x = 0; x < i + 1; x++) cout << str[x]; cout << " "; for (int x = i + 1; x < n; x++) cout << str[x]; count++; // break the loop after printing the palindrom string break; } } // if count is 0 then no palindrome subtring pair found if (count == 0) cout << "NO";} change this code to stdio.h string.harrow_forward
- Pls help ASAP. Language is C#arrow_forwardC Programming Language Note: Input and Output Must be the same Write in C Languagearrow_forwardTAKE A LIST OF STRING FROM THE USER AND COUNT THE NUMBER OF UNIQUE ELEMENTS WITHOUT USING THE FOR, WHILE, Do-WHILE LOOPS. PREFERRED PROGRAMMING LANGUAGE: JAVA/C++arrow_forward
- here is a and b part plz solve c part #include <iostream>#include <string.h>#include <stdlib.h>#include <sstream>#include <cmath>using namespace std; int main(){ /*Variable declarations*/int higestDegree,higestDegree1;int diffDegree,smallDegree;std::stringstream polynomial,addpolynomial;/*prompt for degree*/std::cout<<"Please enter higest degree of polynomial"<<std::endl;std::cin>>higestDegree; std::cout<<"Please Enter highest degree of 2nd polynomial"<<std::endl;std::cin>>higestDegree1;int *cofficient=new int[higestDegree+1];//cofficient array creation for 1st polynomailint *cofficient1=new int[higestDegree1+1];//cofficient array creation for 2st polynomail /*taking cofficient for 1st polynomial*/std::cout<<"Please enter cofficient of each term from higest degree to lowest for 1st polynomial"<<std::endl;for(int i=0;i<=higestDegree;i++){std::cin>>cofficient[i];}/*taking cofficient for 2st…arrow_forwardFix the errors and send the code please // Application allows user to enter a series of words // and displays them in reverse order import java.util.*; public class DebugEight4 { public static void main(String[] args) { Scanner input = new Scanner(System.in); int x = 0, y; String array[] = new String[100]; String entry; final String STOP = XXX; StringBuffer message = new StringBuffer("The words in reverse order are\n"); System.out.println("Enter any word\n" + "Enter + STOP + when you want to stop"); entry = input.next(); while(!(entry.equals(STOP))) { array[x] = entry; ++x; System.out.println("Enter another word\n" + "Enter " + STOP + " when you want to stop"); entry = input.next(); } for(y = x - 1; y > 0; ++y) { message.append(array[y]); message.append("\n"); } System.out.println(message) }arrow_forwardPlease code this in C++. Do not use namespace std. Please use basic code. Thank you for your time. Common Elements Write a program that prompts the user to enter two arrays of 10 integers and displays the common elements that appear in both arrays. Here is a sample run. Enter list1: 8 5 10 1 6 16 61 9 11 2 Enter list2: 4 2 3 10 3 34 35 67 3 1 The common elements are 10 1 2arrow_forward
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