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- Price_($000)/Sq Ft 1/Sq Ft Location 14.0542 0.0653 0 17.2907 0.0524 0 18.3029 0.00649 0 15.7341 0.04374 0 14.8521 0.01913 0 15.3572 0.0197 0 18.3278 0.01583 0 15.8483 0.41563 0 17.392 0.29976 0 15.8826 0.1798 0 15.5492 0.00816 0 14.619 0.0325 0 15.7633 0.21829 0 15.1289 0.015939 0 17.2874 0.18765 0 15.6938 0.00986 0 15.3672 0.03096 0 15.3126 0.01917 0 17.4008 0.06055 0 16.1066 0.0611 0 16.6637 0.1171 1 16.5504 0.05552 1 17.0575 0.00657 1 17.9466 0.1407 1 17.8913 0.0648 1 15.5396 0.03339 1 18.6629 0.03443 1 18.0774 0.019 1 20.8122 0.20162 1 18.3237 0.319 1Find the value of z if the area under a standard normal curve (a) to the right of z is 0.3228; (b) to the left of z is 0.1271; (c) between 0 and z, with z> 0, is 0.4890; and (d) between -zand z, with z> 0, is 0.9500. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.9. A simple random sample of size n is drawn. The sample mean, x, is found to be 18.3, and the sample standard deviation, s, is found to be 4.8. 15 Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about µ if the sample size, n, is 35. ; Upper bound: (Use ascending order. Round to two decimal places as needed.) Lower bound: (b) Construct a 95% confidence interval about µ if the sample size, n, is 61. Lower bound: Upper bound: (Use ascending order. Round to two decimal places as needed.) How does increasing the sample size affect the margin of error, E? O A. The margin of error decreases. O B. The margin of error does not change. C. The margin of error increases. (c) Construct a 99% confidence interval about u if the sample size, n, is 35. ; Upper bound: (Use ascending order. Round to two decimal places as needed.) Lower bound: Compare the results to those obtained in part (a). How does increasing the level of confidence affect…
- Two questions needing to be anwsered * average rate of change *find out z score shaded area between -1.5647 and 1.3698Variable | Obs Mean Std. Dev. Min Маx earnings | e1000 | 41412.69 25527.05 1050 1.05 172000 41.41269 25.52705 172 regress e1000 education Source | SS df MS Number of obs F(1, 169) Prob > F 68.86 Model Residual 32068.6617 32068.6617 0.0000 169 465.730862 R-squared Adj R-squared Root MSE 0.2853 Total | 110777.177 170 651.630455 e1000 | Coef. Std. Err. P>|t| [95% Conf. Interval] 0.000 6.215653 5.021123 31.05591 education 8.30 3.826593 cons 8.887835 -3.49 0.001 -13.51044 Please fill in the boxes below with the missing Stata output values. If needed, please round your answers to 3 decimal places. Number of observations (integer) 78708.515 RSS (4 decimal places) R squared (4 decimal places) Std. Err. for slope
- S DAILY N x 6 WEEK_ x Microsc x S WEEK X O Micros x Micros X S SKILLC X M nbox 128fad3ebd013fc2038e53478cfbbc97a28d/MyFiles/Downloads/Week One_Distance_Midpoint Segment... ddition.pdf 3 / 12 129% Find the coordinates of the midpoint of EF if E(-2, -8) and F(-12, 6). 12.A college entrance exam company determined that a score of 24 on the mathematics portion of the exam suggests that a student is ready for college-level mathematics. To achieve this goal, the company recommends that students take a core curriculum of math courses in high school. Suppose a random sample of 150 students who completed this core set of courses results in a mean math score of 24.6 on the college entrance exam with a standard deviation of 3.3. Do these results suggest that students who complete the core curriculum are ready for college-level mathematics? That is, are they scoring above 24 on the mathematics portion of the exam? Complete parts a) through d) below. Click the icon to view the table of critical t-values. (a) State the appropriate null and alternative hypotheses. Fill in the correct answers below. The appropriate null and alternative hypotheses are Ho versus H₁ (Type integers or decimals. Do not round.) 255A simple random sample of size n is drawn. The sample mean, x, is found to be 18.2, and the sample standard deviation, s, is found to be 4.5. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about u if the sample size, n, is 35. Lower bound: ; Upper bound: (Use ascending order. Round to two decimal places as needed.)
- About ? % of the area under the curve of the standard normal distribution is between z=−0.748z=-0.748 and z=0.748z=0.748 (or within 0.748 standard deviations of the mean).tion 14 For the normal distribution shown below, what area is contained between -2 and 1? -2 -1 3. 2.7. Find the area under the standard normal curve between (-1.35) and the mean?