Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA: “The lowest common ancestor is defined between two nodes p and q as the lowest node in t that has both p and q as descendants (where we allow a node to be a descendant of itself)." For example, in the figure from question 1, the LCA between nodes 5 and 46 is 21. You may use the following typedef structure. The function returns the reference of the node that is considered the LCA. typedef struct node_s{ int data; struct node_s * leftchild; struct node_s * rightchild; }node_t;

Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA: “The lowest common ancestor is defined between two nodes p and q as the lowest node in t that has both p and q as descendants (where we allow a node to be a descendant of itself)." For example, in the figure from question 1, the LCA between nodes 5 and 46 is 21. You may use the following typedef structure. The function returns the reference of the node that is considered the LCA. typedef struct node_s{ int data; struct node_s * leftchild; struct node_s * rightchild; }node_t;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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This question should be answered with OCaml. All functions must be implemented with the Continuation Passing Style. Do not use ChatGPT. Oftentimes we want to traverse an entire tree in a certain order. One common way of traversing a tree is postorder traversal. In postorder traversal, we traverse the left subtree first, then traverse the right subtree, then visit the node. Our job is to create a function that returns a list of the values of the tree visited in postorder traversal. This function should be implemented with the Continuation Passing Style. Our function would have the following signature: traverse : 'a tree -> 'a list Example 1: For the tree in the image above, traverse should return the list [2; 5; 11; 6; 7; 5; 9; 9; 1]. Example 2: Input: Tree (Tree (Empty, 2, Empty), 1, Tree (Empty, 3, Empty)) Output: [2; 3; 1] Example 3: Input: Tree (Tree (Tree (Empty, 4, Empty), 2, Tree (Empty, 5, Empty)), 1, Tree (Empty, 3, Empty)) Output: [4; 5; 2; 3; 1] 1. Write a good set of…
E. D 2. In the binary search tree above, finding node E requires one comparison and finding node A requires four comparisons. What is the expected number of comparisons required to find a node chosen at random?
construct a binary search tree using a set of numbers, similar to the example mentioned in the class. after constructing the BST, you need to give the pre-order traversal of the tree. Finally, you’re required to remove the root of tree. Please show me step by step how to do this!
Build a Binary Search Tree with the given input order. You must show step by step process of inserting the inputs including both recursive calls and tree diagrams for each step. [ refer to the Insertitem function of Lecture 10 slides to get an idea of doing this.] N.B: Unique Input orders for each student to build the tree are given on a separate file. Write down the input order on your answer script before answering the question. You must use the assigned input order. Do not change the order. TREE INPUT: 4,1,9,3,2,5,6,8,7
10.
b. Given a BST whose root node is represented by the node root. Write a function findroots(Node * root) to traverse the BST and print the number of total parent (atleast have a child node) nodes of the BST. N.B: Print order doesn't matter Fig 1: An example Binary Search Tree. 5 For example: In this figure, there are total 4 parents
Given a binary search tree and data of two nodes, find 'LCA' (Lowest Common Ancestor) of the given two nodes in the BST.LCALCA of two nodes A and B is the lowest or deepest node which has both A and B as its descendants. Example:In this example, the green coloured node is the LCA to A and B.Alt TextNote:It is defined that each node is a descendant to itself, so, if there are two nodes X and Y and X has a direct connection from Y, then Y is the lowest common ancestor.Example:Alt TextNote:1. If out of 2 nodes only one node is present, return that node. 2. If both are not present, return -1.3. all the node data will be unique.Input format:The first line of input contains data of the nodes of the tree in level order form. The data of the nodes of the tree is separated by space. If any node does not have left or right child, take -1 in its place. Since -1 is used as an indication whether the left or right nodes exist, therefore, it will not be a part of the data of any node.The following…
= Suppose that we have a B and the size of the search key field V is equal to 10 bytes, the size of the data (record) pointer Pr 6 bytes, and the tree (block) pointer P is 5 bytes and the value of p (the order or the maximum number of a tree pointers in a node) is equal to 20 for an internal node. a) Calculate the block size (B) b) Suppose that we have a B- tree instead of B and based on the block size found in question (a), calculate the order (p) for an internal node in this case.
Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree. According to the definition of LCA on Wikipedia: "The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself)." / 6 1 2 1 0 1 8 7 4 For example, the lowest common ancestor (LCA) of nodes 5 and 1 is 3. Another example is LCA of nodes 5 and 4 is 5, since a node can be a descendant of itself according to the LCA definition.
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