Give a program with 106 instructions divided into classes as follows: 10% class A, 20% class B, 50% class C, and 20% class D   Clock Rate CPI Class A CPI Class B CPI Class C CPI Class D Computer 1 2.5 GHz 1 2 3 3 Computer 2 3.0 GHz 2 2 2 2 What are the clock cycles to execute this program on each computer? What is the average CPI for each computer? Which computer is faster? By how much?

The Little Man Computer Calculator Mailboxes 00 500 01 199 02 500 03 399 In Basket 95 96 97 98 99 123 Out Basket 05 Little man Instruction location counter Reset button 1. The Out instruction copies data from the a. In basket to a mailbox alculator to a mailbox c. In basket to the calculator d. mailbox to the calculator e. calculator to the In basket f. none of the above

Case Study Assume a computer system has a main memory of 256 Bytes. The following is a memory byte-access trace history of a program run on this system. For example, as it is shown, the program first accesses memory address 0000 0000, and then it accesses memory address 0000 0001 and so on. Note the memory addresses are represented in binary: 00000000, 00000001, 00000010, 00000011, 00001000, 00010000, 00010001, 00000100, 00000101, 00000110, 00000111, 00001001, 00001010, 00001011, 00001100, 00001000, 00001001, 00001010, 00011100, 00011101. Q3. Assume the system has a 16-Byte direct mapped unified L1 cache with a block size of 2 Bytes. The following table shows how the cache looks like after the first access to the memory is finished. Please show; in the provided table, how it looks like after the 20th access is finished. You could ignore the "Data" Column. (Add or remove Rows/Columns in the provided table for your answer, as you see fit). Cache contents after the 1st access: Cache Index…

Assume a computer system has a main memory of 256 Bytes. The following is a memory byte-access trace history of  a program run on this system. For example, as it is shown, the program first accesses memory address 0000 0000, and  then it accesses memory address 0000 0001 and so on. Note the memory addresses are represented in binary: 00000000, 00000001, 00000010, 00000011, 00001000, 00010000, 00010001, 00000100, 00000101, 00000110, 00000111, 00001001, 00001010, 00001011, 00001100, 00001000, 00001001, 00001010, 00011100, 00011101.