**Problem Statement:** The volume of a cylindrical can is \(32\pi \, \text{in}^3\). If the height of the can is 2 inches, what is its radius, in inches? **Options:** - \(2 \, \text{in}\) - \(4 \, \text{in}\) - \(8 \, \text{in}\) - \(16 \, \text{in}\) **Explanation:** To find the radius of the cylindrical can, use the formula for the volume of a cylinder: \[ V = \pi r^2 h \] Where: - \( V \) is the volume, - \( r \) is the radius, - \( h \) is the height. Given: - \( V = 32\pi \, \text{in}^3 \) - \( h = 2 \, \text{in} \) Replace the known values into the formula: \[ 32\pi = \pi r^2 \times 2 \] Divide both sides by \(\pi\): \[ 32 = 2r^2 \] Then divide by 2: \[ 16 = r^2 \] Take the square root of both sides: \[ r = 4 \, \text{in} \] Therefore, the radius of the cylindrical can is \(4 \, \text{in}\).

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