Geometric series can be found by transforming f(x)= to series form using 1 4 Maclaurin's series to get 1-X = E=0x² = 1 + x + x² + x³ + x¹ + 1) Why this series diverges at x = 4 while the function is defined. 2) Why this series diverges at x = -4 while the function is defined.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Geometric series can be found by transforming f(x)= to series form using
1
4
Maclaurin's series to get
1-X
= E=0x² = 1 + x + x² + x³ + x¹ +
1) Why this series diverges at x = 4 while the function is defined.
2) Why this series diverges at x = -4 while the function is defined.
Transcribed Image Text:Geometric series can be found by transforming f(x)= to series form using 1 4 Maclaurin's series to get 1-X = E=0x² = 1 + x + x² + x³ + x¹ + 1) Why this series diverges at x = 4 while the function is defined. 2) Why this series diverges at x = -4 while the function is defined.
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