Geometric series can be found by transforming f(x)= to series form using 1 4 Maclaurin's series to get 1-X = E=0x² = 1 + x + x² + x³ + x¹ + 1) Why this series diverges at x = 4 while the function is defined. 2) Why this series diverges at x = -4 while the function is defined.
Geometric series can be found by transforming f(x)= to series form using 1 4 Maclaurin's series to get 1-X = E=0x² = 1 + x + x² + x³ + x¹ + 1) Why this series diverges at x = 4 while the function is defined. 2) Why this series diverges at x = -4 while the function is defined.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 3RE
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Transcribed Image Text:Geometric series can be found by transforming f(x)= to series form using
1
4
Maclaurin's series to get
1-X
= E=0x² = 1 + x + x² + x³ + x¹ +
1) Why this series diverges at x = 4 while the function is defined.
2) Why this series diverges at x = -4 while the function is defined.
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