Generally speaking net torque will give rise to an angular acceleration a. Στ- ια (general equation) Equilibrium problems consider the subset of the general equation where there is no rotation; i.e. a=0. Στ=0 (equilibrium equation) (2)
Generally speaking net torque will give rise to an angular acceleration a. Στ- ια (general equation) Equilibrium problems consider the subset of the general equation where there is no rotation; i.e. a=0. Στ=0 (equilibrium equation) (2)
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Transcribed Image Text:INTRODUCTION:
This experiment will investigate the rotational analog of forces in equilibrium – i.e. torques in
equilibrium. Here we will consider the net Torque acting on a rotating mass, Er around a specified
pivot point. A single torque, t, is directly related to an individual force acting on a rotating object:
T=rx F;
|t| = |r||F|sin0 = rF1, (1)
where r is the position vector indicating the distance from where the force acts to the pivot point.
Only perpendicular components of force with respect to the r vector will contribute to torque.
Generally speaking net torque will give rise to an angular acceleration a.
Στ- Ια
(general equation)
Equilibrium problems consider the subset of the general equation where there is no rotation; i.e.
a=0.
Στ0
(equilibrium equation)
(2)
Transcribed Image Text:THEORY:
1. Starting with equation (2) above and given values on the picture below, solve the force
body diagram pictured for the ratio m,/m2
'N
r2
mig
m2g
mcomg
2. Now, change the location of the pivot point – moving it to the right of the center of mass
a distance r3. Solve the system pictured below using equation (2) for the mass of the
meter stick. This will be equation (3).
AN
m¡g
m2g
mcomg
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