
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Transcribed Image Text:G
Light whose wavelength in air is 600 nm is incident on a soap bubble (n = 1.36). On the
other side of the bubble is air as well. Determine the thickness of the soap bubble if this light is
reflected strongly at this point of incidence.
A B
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- xarrow_forwardA goldfish is swimming inside a spherical bowl of water having an index of refraction n = 1.333. Suppose the goldfish is p 10.4 cm from the wall of a bowl of radius |R| = 15.8 cm, as in the figure below. Neglecting the refraction of light caused by the wall of the bowl, determine the apparent distance of the goldfish from the wall according to an observer outside the bowl. 1.07 Your response differs from the correct answer by more than 10%. Double check your calculations. cm behind the glassarrow_forwardw9 - 1 Light rays from the Sun, which is at an angle of 31.0° above the western horizon, strike the still surface of a pond. What is the angle of reflection of the rays that leave the pond surface?arrow_forward
- Plz do fast asaparrow_forwardComponents of some computers communicate with each other through optical fibers having an index of refraction n = 1.65. What time in nanoseconds is required for a signal to travel 0.17 m through such a fiber? nsarrow_forwarda. A ray of light enters a fiber optic cable with index of refraction n from air at an angle e as shown below. Let the angle 0 be 69°. For total internal reflection to occur at the cable-air interface, what must be the value of n? n = nair = 1 0 θα θα narrow_forward
- Which of the following statements are (or could be) true? Choose all that apply. O A glass at a temperature of 43 K will emit EM waves. O The index of refraction of a newly discovered transparent material is 1.6. In a vacuum, radio waves move the same speed as microwaves. O Total internal reflection will occur if the critical angle is greater than the incident angle. A light ray was reflected. The incident angle was 44° and the reflected angle was 60°. O If do = 0, then d; = f.arrow_forwardCalculate the angle of refraction at the air/core interface, r . critical angle, c and incident angle at the core/cladding interface, i . Will this light ray propagate down the fiber? You have the following data: nair = 1, ncore = 1.46, ncladding =1.43, incident =12o Answers: r = 8.2o , c = 78.4o , i = 81.8o light will propagate Formula summery Index of Refraction n= n sin 01= n, sin 0, o = sin1(2) Snell's Law Critical Angle Acceptance angle a= sin1 Numerical Aperture NA = sin a = ni- nịarrow_forwarda. A ray of light enters a fiber optic cable with index of refraction n from air at an angle e as shown below. Let the angle 0 be 69°. For total internal reflection to occur at the cable-air interface, what must be the value of n? Dair - 1 n = Ꮎ θα ec narrow_forward
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