f(x) = x2 – 2x %3D

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Integral Problem Solving

**Problem Statement:**
2. Write an integral that represents the shaded region on the graph, and then evaluate your integral.

**Graph and Function:**
The graph presented depicts a quadratic function, \( f(x) = x^2 - 2x \), which describes a parabola opening upwards.

**Steps and Explanation:**

1. **Identifying the Bounded Region:** 
   The shaded region under the curve of the function \( f(x) = x^2 - 2x \) needs to be determined. To identify the points that bound this region, we observe the points of intersection where the curve crosses the x-axis. 

2. **Finding Intersection Points:**
   Solve \( x^2 - 2x = 0 \).
   \[
   x(x - 2) = 0
   \]
   This gives us \( x = 0 \) and \( x = 2 \).

3. **Setting Up the Integral:**
   The integral will be set up from \( x = 0 \) to \( x = 2 \), which are the points of intersection. The integral that represents the shaded region is:
   \[
   \int_{0}^{2} (x^2 - 2x) \, dx
   \]

4. **Evaluating the Integral:**
   To evaluate the integral:
   \[
   \int (x^2 - 2x) \, dx = \int x^2 \, dx - \int 2x \, dx
   \]
   Compute each term separately:
   \[
   \int x^2 \, dx = \frac{x^3}{3} + C
   \]
   \[
   \int 2x \, dx = x^2 + C
   \]
   Combine and apply the limits from 0 to 2:
   \[
   \left[ \frac{x^3}{3} - x^2 \right]_{0}^{2}
   \]
   Substitute the upper and lower bounds:
   \[
   \left( \frac{2^3}{3} - 2^2 \right) - \left( \frac{0^3}{3} - 0^2 \right)
   \]
   Simplify:
   \[
   \left( \frac{8}{3} -
Transcribed Image Text:### Integral Problem Solving **Problem Statement:** 2. Write an integral that represents the shaded region on the graph, and then evaluate your integral. **Graph and Function:** The graph presented depicts a quadratic function, \( f(x) = x^2 - 2x \), which describes a parabola opening upwards. **Steps and Explanation:** 1. **Identifying the Bounded Region:** The shaded region under the curve of the function \( f(x) = x^2 - 2x \) needs to be determined. To identify the points that bound this region, we observe the points of intersection where the curve crosses the x-axis. 2. **Finding Intersection Points:** Solve \( x^2 - 2x = 0 \). \[ x(x - 2) = 0 \] This gives us \( x = 0 \) and \( x = 2 \). 3. **Setting Up the Integral:** The integral will be set up from \( x = 0 \) to \( x = 2 \), which are the points of intersection. The integral that represents the shaded region is: \[ \int_{0}^{2} (x^2 - 2x) \, dx \] 4. **Evaluating the Integral:** To evaluate the integral: \[ \int (x^2 - 2x) \, dx = \int x^2 \, dx - \int 2x \, dx \] Compute each term separately: \[ \int x^2 \, dx = \frac{x^3}{3} + C \] \[ \int 2x \, dx = x^2 + C \] Combine and apply the limits from 0 to 2: \[ \left[ \frac{x^3}{3} - x^2 \right]_{0}^{2} \] Substitute the upper and lower bounds: \[ \left( \frac{2^3}{3} - 2^2 \right) - \left( \frac{0^3}{3} - 0^2 \right) \] Simplify: \[ \left( \frac{8}{3} -
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