Ft = m Av p = mv J = Ft What is the average momentum of a 50 kg runner who covers 400 m in 50 s?

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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### Understanding Momentum and Impulse

#### Key Equations:
1. **Momentum**:  
   \( p = mv \)  
   Where:
   - \( p \) is momentum,
   - \( m \) is mass,
   - \( v \) is velocity.

2. **Impulse**:  
   \( J = Ft \)  
   Where:
   - \( J \) is impulse,
   - \( F \) is force,
   - \( t \) is time.

3. **Impulse-Momentum Theorem**:  
   \( Ft = m\Delta v \)  
   Where:
   - \( \Delta v \) is the change in velocity.

#### Problem:
What is the average momentum of a 50 kg runner who covers 400 m in 50 s?

To find the average momentum, we need to follow these steps:

1. **Calculate the average velocity** (\( v \)):
   \[
   v = \frac{\text{distance}}{\text{time}} = \frac{400 \, \text{m}}{50 \, \text{s}} = 8 \, \text{m/s}
   \]

2. **Apply the momentum formula**:
   \[
   p = mv = 50 \, \text{kg} \times 8 \, \text{m/s} = 400 \, \text{kg m/s}
   \]

### Answer:
The average momentum of the runner is 400 kg·m/s.
Transcribed Image Text:### Understanding Momentum and Impulse #### Key Equations: 1. **Momentum**: \( p = mv \) Where: - \( p \) is momentum, - \( m \) is mass, - \( v \) is velocity. 2. **Impulse**: \( J = Ft \) Where: - \( J \) is impulse, - \( F \) is force, - \( t \) is time. 3. **Impulse-Momentum Theorem**: \( Ft = m\Delta v \) Where: - \( \Delta v \) is the change in velocity. #### Problem: What is the average momentum of a 50 kg runner who covers 400 m in 50 s? To find the average momentum, we need to follow these steps: 1. **Calculate the average velocity** (\( v \)): \[ v = \frac{\text{distance}}{\text{time}} = \frac{400 \, \text{m}}{50 \, \text{s}} = 8 \, \text{m/s} \] 2. **Apply the momentum formula**: \[ p = mv = 50 \, \text{kg} \times 8 \, \text{m/s} = 400 \, \text{kg m/s} \] ### Answer: The average momentum of the runner is 400 kg·m/s.
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