f(t) - 3 cos 0.7 Here we define t as the number of seconds elapsed. Also, locations below the resting position have cive values for f. the location of the weight at time t = 2.5. In other words, find f(2.5) . eded, round any decimals to two decimal places. 5) = <-- inches, that the weight is away from its starting position

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.2: Ellipses
Problem 67E
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Modeling with periodic functions: simple harmonic motion. One common application of periodic motion is
the "mass on a spring" model 2. (View another animation of this phenomenon here).
To demonstrate this "simple harmonic motion," a weight is attached to the end of a spring and then stretched
a distance beyond its equilibrium (rest) position. When the weight is released at time t
bounces periodically.
0, the spring then
Below is a function f that models the location of the weight, above or below its resting position, if (when
extended 3 inches beyond its equilibrium) it returns to the starting position every 0.7 seconds:
f(t)
3 cos
0.7
Note: Here we define t as the number of seconds elapsed. Also, locations below the resting position have
negative values for f.
2.5. In other words, find f(2.5).
Find the location of the weight at time t
If needed, round any decimals to two decimal places.
f(2.5) =
<-- inches, that the weight is away from its starting position
Transcribed Image Text:Modeling with periodic functions: simple harmonic motion. One common application of periodic motion is the "mass on a spring" model 2. (View another animation of this phenomenon here). To demonstrate this "simple harmonic motion," a weight is attached to the end of a spring and then stretched a distance beyond its equilibrium (rest) position. When the weight is released at time t bounces periodically. 0, the spring then Below is a function f that models the location of the weight, above or below its resting position, if (when extended 3 inches beyond its equilibrium) it returns to the starting position every 0.7 seconds: f(t) 3 cos 0.7 Note: Here we define t as the number of seconds elapsed. Also, locations below the resting position have negative values for f. 2.5. In other words, find f(2.5). Find the location of the weight at time t If needed, round any decimals to two decimal places. f(2.5) = <-- inches, that the weight is away from its starting position
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