FST = 1 - (H₂/Ht), where H, = He averaged over subpopulations and Ht = H₂ if all samples came from the same population (i.e., the subpopulations combined) Population p q Subpop 1 0.7 0.3 Subpop 2 0.5 0.5 Subpop1 Subpop2 Hs = (H₂ + H₂)/2 Ht = He₁+2 = He calculated from p and q = 2pq 11. Given the table above, the expected heterozygosity of Subpop 1 (He) is 12. Given the table above, the expected heterozygosity of Subpop 2 (H₂₂) is 13. Given the table above, the mean of the expected heterozygosities of Subpop 1 and 2 (H) is 14. Given the table above, the expected heterozygosity of the two populations combined (H₂) is 15. Given your answers to Questions 13 and 14, FST is

Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Chapter21: Microevolution: Genetic Changes Within Populations
Section: Chapter Questions
Problem 8TYK: If the genotype frequencies in a population are 0.60 AA, 0.20 Aa, and 0.20 aa, and if the...
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THIS IS A 4 PART QUESTION. PLEASE EXPLAIN EACH PART’S ANSWERS
FST = 1- (Hs/Ht),
where Hs = He averaged over subpopulations and Ht = He if all samples
came from the same population (i.e., the subpopulations combined)
Population p 9
Subpop 1 0.7 0.3
Subpop 2 0.5 0.5
Subpop1
Subpop2
Hs = (H₁₂ + H₂₂)/2
Ht = He₁+2
= He calculated from p and q
= 2pq
11. Given the table above, the expected heterozygosity of Subpop 1 (He) is
12. Given the table above, the expected heterozygosity of Subpop 2 (H₂) is
13. Given the table above, the mean of the expected heterozygosities of Subpop 1 and 2 (H₂) is
14. Given the table above, the expected heterozygosity of the two populations combined (H₂) is
15. Given your answers to Questions 13 and 14, FST is
Transcribed Image Text:FST = 1- (Hs/Ht), where Hs = He averaged over subpopulations and Ht = He if all samples came from the same population (i.e., the subpopulations combined) Population p 9 Subpop 1 0.7 0.3 Subpop 2 0.5 0.5 Subpop1 Subpop2 Hs = (H₁₂ + H₂₂)/2 Ht = He₁+2 = He calculated from p and q = 2pq 11. Given the table above, the expected heterozygosity of Subpop 1 (He) is 12. Given the table above, the expected heterozygosity of Subpop 2 (H₂) is 13. Given the table above, the mean of the expected heterozygosities of Subpop 1 and 2 (H₂) is 14. Given the table above, the expected heterozygosity of the two populations combined (H₂) is 15. Given your answers to Questions 13 and 14, FST is
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