From the given, calculate: 1. Melt water temperature change 2. Heat lost by water (show all calculations)

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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From the given, calculate:

1. Melt water temperature change

2. Heat lost by water

(show all calculations)

Data Sheet
Time (s)
T (°C)
Time (s)
T (°C)
Time (s)
T (°C)
40°C
180
16.4°C
360
4.8°C
20
39.9°C
39.6°C
200
12.2°C
380
4.5°C
4.2°C
40
220
10.4°C
400
60
80
37°C
33.6°C
420
440
240
7.9°C
7.6°C
4°C
4°C
260
100
30.3°C
280
5.8°C
460
4°C
4°C
5.5°C
5°C
4.9°C
120
26.1°C
300
480
140
160
22.4°C
320
500
520
4°C
18°C
340
4°C
Hot water volume,V1
Hot water initial temperature, T1
Final water volume,V2
Final water temperature, T2
100mL
155.6 mL
40°C
4°C
Given: 25g ice cubes
100g water at 40 °C (p40 = 0.9932 g/mL).
Transcribed Image Text:Data Sheet Time (s) T (°C) Time (s) T (°C) Time (s) T (°C) 40°C 180 16.4°C 360 4.8°C 20 39.9°C 39.6°C 200 12.2°C 380 4.5°C 4.2°C 40 220 10.4°C 400 60 80 37°C 33.6°C 420 440 240 7.9°C 7.6°C 4°C 4°C 260 100 30.3°C 280 5.8°C 460 4°C 4°C 5.5°C 5°C 4.9°C 120 26.1°C 300 480 140 160 22.4°C 320 500 520 4°C 18°C 340 4°C Hot water volume,V1 Hot water initial temperature, T1 Final water volume,V2 Final water temperature, T2 100mL 155.6 mL 40°C 4°C Given: 25g ice cubes 100g water at 40 °C (p40 = 0.9932 g/mL).
Hot water mass: m hot = V1'p
%3D
4
Total water mass: m total = V2°p
Melt water mass: m melt = m total – m hot
Hot water temperature change: AT hot = T2– T1
Melt water temperature change: AT melt = T2 – 0.0 °C
Heat lost by hot water: q hot = Cp · m hot · AT hot
Heat gained by melt water: q melt = Cp · m melt · AT melt
Heat absorbed by melting ice: q fusion = (g hot + q melt)
9.
fusion
Heat absorbed per mole: ² H fus
molesmelt
% difference from accepted value:
Transcribed Image Text:Hot water mass: m hot = V1'p %3D 4 Total water mass: m total = V2°p Melt water mass: m melt = m total – m hot Hot water temperature change: AT hot = T2– T1 Melt water temperature change: AT melt = T2 – 0.0 °C Heat lost by hot water: q hot = Cp · m hot · AT hot Heat gained by melt water: q melt = Cp · m melt · AT melt Heat absorbed by melting ice: q fusion = (g hot + q melt) 9. fusion Heat absorbed per mole: ² H fus molesmelt % difference from accepted value:
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