From the figure as shown, determine the stress in psi at the top surface of the second cylinder. Assume the specific weight of the material is 460 Ibf/ft? F = 3000lbf d = 1 ft h = 1.5 ft

That answer to this question is P=5.83kN. I just need help getting to it. Thank you in advance

-8 in.- -8 in.- (a) (b) Which of the following best explains why cylinder (b) has a higher longitudinal stress in its walls compared to cylinder (a)? Assume the gauge pressure of the fluid inside the cylinder is non-zero. O Cylinder (b) is supported at two locations Cylinder (a) is not free to deform in its longitudinal direction The vertical (longitudinal) pressure in cylinder (a) is transferred directly to the [bottom] support, bypassing the cylinder walls None of the above the longitudinal stress for both cylinders is the same

Assemble a pair of parts A and B with serrated teeth as shown in the figure on the right.A compressive load of 24 kN is acting on the combined structure.The compressive load is transmitted by the three meshing teethTo. Shear stress and compressive stress (contact) generated in the tooth at this timeFind each tactile stress.

Determine the resulting maximum value of the normal stress. Specify the orientation of the plane on which these maximum values occur.   **The answer is tensile stress is 0 ksi at 90 degrees.  **The answer is compressive stress is 7 ksi at 0 degrees.  Can you explain how that is? This was my thought process: I know that tensile would be zero because the force P is actually going inwards and not outwards. I know that means that there would be a compressive force. I am confused on the angles, how is a tensile force going 90 degress if there technically is no force in the tensile direction. And how is there a compressive force at 90 degrees if there is a stress? thank you!

Please full solution with the drawing. Big and clear handwriting