
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Is my stereochemistry correct? I don’t know which carbon the the acid attacks so I don’t know if I have the right stereochemistry. It has to look like the top one.

Transcribed Image Text:04
From
Hz SO4
conc.
2)
mcPBA
EPEAS
+EN
+ EN
4.
3)
->
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- Only typed solutionarrow_forward13arrow_forwardUse the information in the pK₂ table below to determine which side of the equilibrium is favored for each of the reactions in the second table. acid pK₂ acid pk₁ H₂ NH₂ X OH NH3 NH CH,SH₂ CH₂- 36 36 15.9 10.8 5.3 N + NH₂ OH + CH₂OH + CH,NH, CH₂OH CH₂-S -OH O OH Š CH₂SH₂ CH3NH 36 ΝΗ 19 15.7 9 Equilibrium Equation -2 -7.2 NH CH₂0 + H CH₂- NH₂ -fo + CH, SH + CH,NH, + NH₂ Left Equal Favored O O O O O O Right Favored O O O O Oarrow_forward
- 2. What products would be obtained by treating A-D with NaOt-Bu in t-BuOH? Explain your reasoning, and if more than one product forms, indicate which product is major. Br A Br B C لي Br Darrow_forwardDraw the major organic product(s) of the following reaction. Br + NaCN DMF • You do not have to consider stereochemistry. • If no reaction occurs, draw the organic starting material. • When SN1 & E1 pathways compete, show both the substitution and the elimination products. Separate multiple products using the + sign from the drop-down menu. .Do not include counter-ions, e.g., Na+, I, in your answer. ? n ChemDoodlearrow_forwardWhy is compound la stonger base than compound I? H - H N. II O 1. Because compound II is more sterically hindered. O2. Because compound I is more stable than compound II. O 3. Because the lone pair on compound Iis part of a delocalized pi-system. O4. Because the lone pair on compound II is part of a delocalized pl-system.arrow_forward
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