Answered: From a large number of actuarial exam…

From a large number of actuarial exam scores, a random sample of 275 scores is selected, and it is found that 187 of these 275 are passing scores. Based on this sample, find a 90%

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: during production of detergent. In people with no lung dysfunction, a typical air flow rate is 0.80.…

A: As the population standard devoation is known, we will use z distribution. The value of z at the…

Q: test. It was found that 80 of them scored higher than 100. Based on this, compute a 95% confidence…

A: According to the given information in this question We need to construct 95% confidence interval

Q: Out of a sample of 600 adults aged 18 to 30, 162 still lived with their parents. Based on this,…

Q: A random sarmple of ni = 268 people who live in a city were selected and 120 identified as a "dog…

A: Given n1=268, X1=120, n2=117, X2=59

Q: A university financial aid office polled a random sample of 467 male undergraduate students and 574…

A: Confidence interval: The (1-α)100 % confidence interval for proportion p1 – p2 is given by,…

Q: A simple random sample of size n=40 is drawn from a population. The sample mean is found to be…

A: n=40 X-bar=121.2 S=13.2 99℅ confidence interval

Q: A simple random sample of size n=16 is drawn from a population that is normally distributed. The…

A: Given information : Sample size = n = 16 Sample mean = x = 66 Sample standard deviation = s = 19…

Q: A scientist wondered if there was a difference in the average daily intake of dairy products between…

A: Reviewing information, X : Daily intake of dairy products of MenY : Daily intake of dairy products…

Q: Compute for a 90% confidence interval estimate for µ=mean score in the reading comprehension test of…

Q: A simple random sample of size n=17 is drawn from a population that is normally distributed. The…

A: The random variable X follows approximately normal distribution. The sample size is 17. The sample…

Q: The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT)…

A: Since, the population variances are unknown the Student's t-test will be applied. The variances are…

Q: The Graduate Schools take a random sample of recent MS graduates (n=135) and finds that 12 of these…

A: Givenn=135x=12confidence interval = 90%p^=xn=12135=0.0889α=1-0.90=0.10α2=0.05zc=zα2=z0.05=1.6449…

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120 significance level =…

Q: A random sample of n1 = 229 people who live in a city were selected and 105 identified as a "dog…

Q: A sample of 15 found that 43.2% of those sampled consumed more than 2 alcoholic beverages a week.…

Q: A simple random sample of size n=15 is drawn from a population that is normally distributed. The…

A: Given information: n=15 x=57 s=20 Confidence level is 95% Significance level is 5%=0.05…

Q: A survey of 100 customers showed that 36 of them preferred brand B of a particular product. Give a…

A: p = proportion of people vote for BSample size : n = 100Number of favorable outcomes : x =…

Q: A random sample of n1n1 = 272 people who live in a city were selected and 74 identified as a "dog…

Q: A random sample of high school students is used to estimate the mean time all high school students…

A: Solution: From the given information, a 99% confidence interval is 1.7 hours to 3.1 hours.

Q: A random sample of n₁ = 276 people who live in a city were selected and 112 identified as a "dog…

A: given data n1 = 276 x1 = 112p^1 = x1n1 = 112276 = 0.4058 n2 = 117 x2 = 70p^2 = x2n2 = 70117…

Q: Use a= .05 and two tailed test t= 1.25, df = 40. reject, fail to reject

A: Given α = 0.05, two tailed test, t = 1.25 and degree of freedom = 40.For a two tail test if test…

Q: A random sample of 200 adults was given an IQ test. It was found that 90 of them scored higher than…

A: From the provided information, Sample size (n) = 200 From which 90 have score higher than 100 (IQ).…

Q: A random sample of elementary children is to be selected to estimate the proportion p who have…

Q: A random sample of n₁ = 252 people who live in a city were selected and 74 identified as a "dog…

A: Given: n1 = 252 X1 = 74 n2 = 111 X2 = 66 Confidence level = 99% Formula Used: Confidence interval =…

Q: A random sample of 500 males included 215 that approved of the performance of a President. A random…

A: Solution-: Given: n1=500,n2=500,x1=215,x2=185,α=0.05 We want to calculate (a) p1^, and q1^, p2^,…

Q: A random sample of n₁ = 213 people who live in a city were selected and 91 identified as a "dog…

A: n1=213x1=91n2=120x2=67α=1-0.90=0.10

Q: random sample of 150 adults was given an IQ test. It was found that 72 of them scored higher than…

Q: A simple random sample of size n=450 individuals who are currently employed is asked if they work at…

A: From given data we have : n=450 x=27 so, Point estimate is p^=xn =27450 =0.06

Q: A random sample of n1 = 258 people who live in a city were selected and 74 identified as a "dog…

A: given data n1 =258 x1 = 74p^1 = x1n1 = 74258 = 0.2868 n2 = 102 x2 = 63 p^2 = x2n2 = 63102 =…

Q: In a science fair project, Emily conducted an experiment in which she tested professional touch…

A: Given data, n=330 x=155 sample proportion p=x/n =155/330=0.47 z-value at 95% confidence is zc=1.96

Q: A student conducted a test to see if people preferred one of two possible new logos for UF, one with…

A: Confidence interval is a technique of estimation.

Q: A high school is running a campaign against the over-use of technology in teens. The committee…

A: sample size(n1)=200sample proportion()=0.85sample size(n2)=180sample proportion()=0.55confidence…

Q: A researcher surveys a group of college students to determine the negative life events that they…

A: The given values are

Q: Each person in a random sample of 234 residents in a major town was asked whether they had ever been…

Q: In a random sample of 250 students who enrolled in Science, 150 took notes during classes. Find an…

A: Given that n=250,x =150,alpha =0.05 Find an approximate 95% confidence interval for the population…

Q: A random sample of n = 246 people who live in a city were selected and 76 identified as a "dog…

A: We have given that, X1 = 76 , N1 = 246 and X2 = 69, N2 = 115 Then, We will find the 90% confidence…

Q: In a random sample of 392 people that were tested for the Norcovirus, it was found that 314 did not…

A: The objective of this question is to understand the meaning of the given 97% confidence interval for…

Q: Part A: Construct and interpret a 95% confidence interval for the difference in population…

A: Let is the difference between population proportions of females and males who have an after-school…

Q: A sample of size 25 was taken from a very large population. Sample statistics, x¯ and s, were used…

Q: Alessandro constructed three confidence intervals, all from the same random sample. The confidence…

A: As the confidence level increases, the width of the confidence interval increases. The width of the…

Q: A random sample of n₁ = 261 people who live in a city were selected and 107 identified as a "dog…

A: Suppose p1 is the true population proportion of people that live in the city who identify as a “dog…

Q: A random sample of 500 males included 215 that approved of the performance of a President. A random…

A: Given X1=215 X2=185 n1=n2=500

Q: ndom sample of size n=40 is drawn from a population. The sample mean is found to be x=121.3 and the…

A: As the population standard deviation is not known, we will use t distribution. df=n-1=40−1=39, and…

Question

From a large number of actuarial exam scores, a random sample of

275

scores is selected, and it is found that

187

of these

275

are passing scores. Based on this sample, find a

90%

confidence interval for the proportion of all scores that are passing. Then find the lower limit and upper limit of the

90%

confidence interval.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

A random sample of n₁ = 217 people who live in a city were selected and 106 identified as a "dog person." A random sample of n₂ = 114 people who live in a rural area were selected and 66 identified as a "dog person." Find the 90% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < P1 P2 <
A random sample of n1n1 = 236 people who live in a city were selected and 90 identified as a "dog person." A random sample of n2n2 = 103 people who live in a rural area were selected and 56 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. ___________< p1−p2p1-p2 <_____________
A random sample of n1 = 213 people who live in a city were selected and 80 identified as a "dog person." A random sample of n2 = 98 people who live in a rural area were selected and 61 identified as a "dog person." Find the 90% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. Рі — Р2
find the t sub alpha/2 when n=23 for the 95% confidence interval.
A random sample of 500 patients with diabetes were weighed before and after switching to a new drug and the change in their weight is computed for each patient. The resulting 90% confidence interval for the average change in the weight of diabetes patients is (1, 5) expressed in pounds. Which of the following can be the 95% confidence interval generated from the same data?
A researcher surveys a group of college students to determine the negative life events that they experienced in the past 5 years and their current feeling of well-being. For N = 18 participants with 2 or fewer negative experiences, the average well-being score was X = 42 with SS = 398. For the N = 16 participants with 5 to 10 negative experiences the average score is X = 48.6 with SS = 370. Construct a 95% confidence interval for the difference between the population means for the two groups.
We wish to estimate what percent of adult residents in a certain county are parents. Out of 100 adult residents sampled, 48 had kids. Based on this, construct a 90% confidence interval for the proportion ππ of adult residents who are parents in this county.
A random sample of n₁ = 224 people who live in a city were selected and 90 identified as a "dog person." A random sample of n₂ = 95 people who live in a rural area were selected and 61 identified as a "dog person." Find the 95% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. P1 P2
A random sample of n₁ = 269 people who live in a city were selected and 88 identified as a "dog person." A random sample of n2 = 90 people who live in a rural area were selected and 70 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < P1 P2 <
In order to estimate the average GPA of all students at SCC, we selected a random sample of 36 students and found that their average GPA is 2.1 with a s. d. of 0.8.Construct a 95% confidence interval for the average GPA of all students at SCC.
In a science fair project, Emily conducted an experiment in which she tested professional touch therapists to see if they could sense her energy field. She flipped a coin to select either her right hand or her left hand, and then she asked the therapists to identify the selected hand by placing their hand just under Emily's hand without seeing it and without touching it. Among 337 trials, the touch therapists were correct 163 times. Using Emily's sample results, construct a 95% confidence interval estimate of the proportion of correct responses made by touch therapists. (round to 3 decimal places)
A random sample of ni = 262 people who live in a city were selected and 104 identified as a "dog person." A random sample of n2 = 117 people who live in a rural area were selected and 50 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < pi - P2 -