Four solutions of an acid dissolved in water are sketched below, as if under a microscope so powerful individual atoms could solution is shown in each sketch. Rank the solutions by the strength of the dissolved acid. That is, select 1 under the solution of the strongest acid, 2 under the solution of the next strongest acid, and so on. Note: seen. The same volume of = H₂O

1.  Hydrocyanic acid (HCN) is a weak acid, a hydrocyanic (HCN) gas solution in water. c)  Consider the aqueous solution of HCN acid. Is the molarity of H3O ion higher or lower than the molarity of HO- ion? d)  WhatisthemolarityofhydroniumionsinasolutionofHCNwithpH=6.5? e)  AssumeyouaddedacertainmassofNaCNintothesolutionofHCN.Describewhatwouldbean essential property of this solution?

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QUESTION 9 The following pictures repreşent equal volumes of aqueous solutions of three acids HA (A = X, Y, or Z); water molecules have been omitted for clarity. O = HA = H,O* HX HY HZ Arrange the acids in order of increasing pH. O HZ < HY < HX HX < HZ < HY O HZ < HX < HY O HY < HZ < HX Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All MacBook Ain DD 80 000 000 F8 F9 F6 F7 F4 F5 F2 F3 & C@ %23 7. 8. %24

A solution is made from 0.39 M HF and 0.31 M NaF. What is the pH of the K, for HF is 6.8x10 4? Express your answer to two decimal places.

[References] A chemist prepares dilute solutions of equal molar concentrations of CH3 NH,, CH3 NH, CI, NaNO,, and NaNO3 Rank these solutions from highest pH to low pH. (K, for CH3 NH2 is 4.4 x 10 K. for HNO, is 4.5 x 10 4.) Decreasing of pH Drag and drop your selection from the following list to complete the answer CH,NH2 NaNO; CH;NH3 CI NaNO,

Acid strength decreases in the series HI > HS04 > HF > HCN. Which of these equal molar salt solutions will have the highest pH in water? NazSO4 More information is needed to make a determination. Nal NaCN NaF

Determine the molar concentration of each ion present in the solutions that result from each of the following mixtures:(Disregard the concentration of H+ and OH- from water and assume that volumes are additive.) c) 30.8mL of 0.305M NaOH and 24.1mL of 0.241M HCl M Na+= M Cl-= M H+= M OH-= d) 11.7mL of 0.760M H2SO4 and 22.2mL of 0.185M NaOH M Na+= M SO4 2-= M H+= M OH-=

Initial pH: 1.55 Molarity: 0.081158

An acid (HA) has a % Ionization of 2.1%. A solution of this acid has a molarity of 0.500 M. Determine the Ka of this acid.