
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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I need help with how to solve this table. Please help with the equations and steps to solve this.
![HOMEWORK EXERCISES
1. Four runs are performed by mixing the reagents as indicated at 25 °C. Calculate the
concentration of each reactant using the dilution formula. The total volume of each run is
100.00 mL. Note: A[Se] = [H2SEO3]
H2SEO3 + 6 I + 4 H → Se + 2 13 + 3 H20
Run 1
25.00 mL of 0.200 M H2SEO3
Run 2
50.00 mL of 0.200 M H,SeO3
Run 3
25.00 mL of 0.200 M H2SEO3
Run 4
25.00 mL of 0.200 M H,SeO3
25.00 mL of 1.20 M KI
25.00 mL of 1.20 M KI
50.00 mL of 1.20 M KI
25.00 mL of 1.20 M KI
25.00 mL of0.800 M HCI
25.00 mL of 0.800 M HC1
25.00 mL of 0.800 M HCI
50.00 mL of 0.800 M HCI
25.00 mL KCI
Run
[H,SeO3]o
[I ]o
[H*],
A [Se]
Δt
Rate (A[Se]/At)
k
Units
sec
1
300
300
37.5
75
3.
4+](https://content.bartleby.com/qna-images/question/b234898a-ca00-4740-ae3d-79576f672843/03aa10df-507f-4a4e-82b9-80ae701cc900/8jv0dba_thumbnail.jpeg)
Transcribed Image Text:HOMEWORK EXERCISES
1. Four runs are performed by mixing the reagents as indicated at 25 °C. Calculate the
concentration of each reactant using the dilution formula. The total volume of each run is
100.00 mL. Note: A[Se] = [H2SEO3]
H2SEO3 + 6 I + 4 H → Se + 2 13 + 3 H20
Run 1
25.00 mL of 0.200 M H2SEO3
Run 2
50.00 mL of 0.200 M H,SeO3
Run 3
25.00 mL of 0.200 M H2SEO3
Run 4
25.00 mL of 0.200 M H,SeO3
25.00 mL of 1.20 M KI
25.00 mL of 1.20 M KI
50.00 mL of 1.20 M KI
25.00 mL of 1.20 M KI
25.00 mL of0.800 M HCI
25.00 mL of 0.800 M HC1
25.00 mL of 0.800 M HCI
50.00 mL of 0.800 M HCI
25.00 mL KCI
Run
[H,SeO3]o
[I ]o
[H*],
A [Se]
Δt
Rate (A[Se]/At)
k
Units
sec
1
300
300
37.5
75
3.
4+
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