Four resistors are connected to a battery with a terminal voltage of 12 V, as shown in the figure below. (Assume R₁ = 39.0 and R₂ = 70.0 2.) R₁ 50.0 Ω 20.0 Ω www R₂ + 12 V ( (a) How would you reduce the circuit to an equivalent single resistor connected to the battery? Use this procedure to find the equivalent resistance of the circuit. Ω (b) Find the current delivered by the battery to this equivalent resistance. A (c) Determine the power delivered by the battery. W (d) Determine the power delivered to the 50.0-2 resistor.

An engineer built the circuit depicted in the figure. Assuming & = 7.60 V and R = 4.70 , find the following quantities. 12.0 V + a E + Need Help? ㅏ 2.00 Ω www = -3.8453 www 4.00 Ω ww R (a) the current in the 2.00 resistor (Enter the magnitude in mA.) 718.232 mA Read It (b) the potential difference (in V) between points a and b Vb - Va= X Apply Ohm's law and your result from part (a) to calculate your answer. It might help to redraw the circuit so that points a and b are clearly defined junctions. V b

Consider the circuit shown in the figure below. (Let R = 18.0 02.) 25.0 V 5.00 Ω a 10.0 Ω W 10.0 Ω -MW ww 5.00 Ω b (a) Find the current in the 18.0- resistor. A R (b) Find the potential difference between points a and b. V

Consider the circuit shown below. (a)Determine the equivalent resistance and the current from the battery with switch ?1 open. (b) Determine the equivalent resistance and the current from the battery with switch ?1closed.