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Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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
Transcribed Image Text:Four pounds of air gain 0.491 Btu/°R of entropy during a non-flow
isothermal process. If P1 = 120 psia and V2 = 42.5 ft3, find a. V1 and
T1 b. Wn c. Q and d. Change in U.
%3D
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- t = 135°C, h = 567.69 KJ/kgarrow_forwardProvide a complete solution and answer for the given problem in the attached image.arrow_forwardYou have a tank that is 0.01 m^3 and is initially evacuated. You then hook this up to a line that supplies N2 at a pressure of P_1 = 5 bar and a T_1 = 350 K. The tank fills adiabatically (you can assume there is no heat flow to the walls of the tank), and the filling ends when no more N2 flows into the tank. Find a) the final pressure of the gas in the tank, and b) the final temperature of the gas in the tank. You can assume N2 is an ideal gas with a CP* = 29 J/mol K. NOTE: Mainly I am confused on how the evacuated tank factors into the work for b). What I did was use the ideal gas formula to find a value for N2*T2 (601.395) but I am no longer certain how to continue in the work. I was assuming the practice question had meant the temperature of the tank was 0 initially but it leads to a negative mole value. For a) I got 5 bar, arguing the flow would stop when the pressure of tank and line are equalarrow_forward
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