Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution freezing point boiling point 3.6 g of hydrobromic acid (HBr) dissolved in 400. mL of water (choose one) (choose one) v 3.6 g of potassium iodide (KI) dissolved in 400. mL of water 3.6 g of glucose (C6H12O6) dissolved in 400. mL of water (choose one) v (choose one) (choose one) (choose one) v 400. mL of pure water (choose one)v (choose one) v G

PROVISIONAL LEWIS STRUCTURES T01/S01 For each provisional structure, identify if it is the correct Lewis structure (C) or if it needs to be modified according to procedure MA or MB to obtain the correct Lewis structure. MA. Form multiple bonds to the central atom using lone pair on the terminal atom(s) until the central atom has an octet (or septet). MB. Form multiple bonds to the central atom using lone pair on the terminal atom(s) until the central atom has a formal charge of zero (0) or until two double bonds are formed. A provisional structure has the valence electrons distributed in order as (1) a bond between each pair of atoms, (2) an octet for each ligand (terminal) atom or ligand group (CH3, NH2 or OH) and (3) any remaining electrons on the central atom.

(1) Br2 CC,

Le Chateliers principle. 7 / + 3 Beg) = 2 A#= +60,000 Inc [B] Dec [D] Inc [C] €² 2 C + D (2) до Inc. I Дес Р

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There are three possible Grignard reactions that lead to the given alcohol. Select the reactant needed for each of the indicated Grignard reagents. MgBr 1) ? 2) HO oi or OH OH of