Four equal resistances are connected in parallel across a certain supply (V) producing a power P. How much power (in terms of P) will be produced if the resistances are connected in series across the same supply (V)?

A potential difference of 120 V is applied across a resistor of unknown resistance. If the heat dissipated in the resistor is 100W, what is the value of the resistance?

The figure below shows a multiloop circuit. The voltages and resistances in the circuit are: V1 = 10.0 V, V2 = 30.0 V, V3 = 58.0 V, R1 = 125.0 Ω, R2 = 155.0 Ω, R3 = 195.0 Ω. Use these values to answer the questions below. (Use the following as necessary: I1, I2, and I3.) (a) Write the equation for the loop ABHEFGA in the order that you go around the loop. −I2 (155.0 Ω) −30.0 V + 10.0 V − I1 (125.0 Ω) = 0 +I2 (155.0 Ω) +30.0 V +10.0 V − I1 (125.0 Ω) = 0 +I3 (155.0 Ω) +58.0 V −10.0 V − I2 (155.0 Ω) = 0 −I3 (195.0 Ω) −58.0 V +10.0 V − I1 (155.0 Ω) = 0 (b) Write the equation for the loop BCKDEHB in the order that you go around the loop. +I2 (155.0 Ω) +30.0 V +10.0 V − I1 (125.0 Ω) = 0 +I3 (195.0 Ω) −58.0 V + 30.0 V + I2 (155.0 Ω) = 0 +I3 (155.0 Ω) +58.0 V −10.0 V − I2 (155.0 Ω) = 0 −I3 (195.0 Ω) −58.0 V +30.0 V − I1 (155.0 Ω) = 0 (C)Write the equation for the loop ABCKDEFGA in the order that you go around the loop. +I3 (155.0 Ω) +30.0 V −58.0 V − I2 (125.0 Ω) = 0 −I3 (195.0 Ω)…

The constant potential difference across a 2 ohm resistor is 20 volts. How many watts of power are dissipated by this resistor?