Four charges with equal amount 6.15 mC are separately 42 F43 placed at the four corners of a square d=0.100 m on a side, as shown in the figure. Determine the magnitude and direction of the force on charge Q4. d

What is the resultant magnitude and direction of the force on a 5.9 µC charge situated on the y-axis, 5.3 cm from the point of origin, due to a pair of 4.3 µC charges located on the x-axis at opposite sides of the point of origin, each at distance of 4.4 cm from the point of origin? a. 17.2 N b. 74.0 N c. 73.0 N d. 76.0 N e. 61.4 N The surfaces of a lipid bi-layer forming the membrane around a cell with a radius of 1.8 µm has a residual charge qr = 10.6x10-15 C on outside of the bi-layer, and the same amount of negative charge on the inside. What is the force in pN (x10-12 N) on a singly-charged positive ion (q =1.6 ×10-1⁹ C) located on the outer surface of this membrane? Hint: Use F = q E = q (o/e) with o = qr/A = qr/ (4π r²) and = 8.85 x 10-12 F.m-1. Answer:

Five identical point charges, each having charge Q, are equally spaced on a semicircle of radius R as shown in the figure. Find the Force (in terms of k, Q, and R) on a charge q located at the center of the semicircle. See attachments

As shown below, an alpha particle (m = 6.642 × 10-27 kg, q = +2e) is shot upward with an initial speed of v; = 3.50 x 105 m/s from one large plate of charge toward another large plate of 8. charge. Each plate has a charge density given below. Assume gravity is negligible. а. Find the speed of the alpha particle once it hits the positively charged plate. b. Which plate is at the higher potential, the top plate or the bottom plate? Explain using physical reasonng. 02 = +2.50 µC/m² 2.00 mm V; = 3.50 × 10° m/s 01 = +4.50 µC/m²

IP A particle with a mass of 4.0 g and a charge of +5.0x10-2 μC is released from rest at point A in the figure (Figure 1). Figure Ag 3.0 cm во 5.0 cm 4.0 cm OC E 1 of 1 L X > In which direction will this charge move? Positive Y- direction Negative y- direction Negative x-direction Positive x-direction Submit Part B V= Request Answer What speed will it have after moving through a distance of 5.5 cm ? The electric field has a magnitude of 1600 N/C Express your answer using two significant figures. 15. ΑΣΦ SFR P Pearson ? m/s

WCLN.ca PHYSICS I2 Coulombs Law in 2D: 1. Electric Force is a vector. Three charged objects are located at the 'corners' of an equilateral triangle with sides 1.0 m long. Two of the objects carry a charge of 5.0 µC each. The third object carries a charge of-5.0 uC. Assume all three objects are very small. Draw the three charges below. Draw the forces acting on the -5.0 µC charge. a. b. Using your diagram above draw the vector diagram showing how you would arrive at the direction of the Net Force acting on the -5.0 µC charge. Determine the angles inside your vector diagram and label them directly onto the sketch. С. What is the resultant force acting on the -5.0 µC object? rao ic fixed 25 cm

Two charges Q=29µC and Q2=-.56µC are placed on a semi-circle with a radius R=11mm as shown in the figure below. How much work must be done to bring a third charge Q3=6µC from infinity to point P. Express your answer in units of Joules using zero decimal places. Take Coulomb constant as k=9.0x109 N.m2/c2. Please do not forget the minus sign if your answer is negative. Q2 Q1 R P

In the figure, the point charges are located at the corners of an equilateral triangle 29 cm on a side. What is the direction of the force on qa in degrees above the negative x-axis with origin at qa?

Two equally charged, 1.00 g spheres are placed with 4.00 cm between their centers. 2 When released, each begins to accelerate at 225 m/s . As the spheres move, do you expect the force between them to increase, decrease or remain the same? Use an equation to justify your reasoning. Calculate the spacing needed between the spheres that would cut the force between them in half.

O O Three 2.50 mC charges are placed on tiny conducting spheres at the ends of 1.00 m-long strings that are connected at 120° angles as shown below. The magnitude, in N, of the force on the knot at the center is Select one: 5.63 x 10 -2 b. 3.75 x 10 2 C. 6.5x 10-2 d. 0. e. 7.5x 10 2