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Formula: C9H10O3 . Determine the structure of the compound given the data shown in the pictures. Explain how you arrived at the answer.
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- 6. C8H100 11 TRANSMITTANCE LOD HSP-04-492 0+ 10 4000 9 3000 8 5 7 6 : 5 ppm 2000 4 HAVENUMBERI-l 2: 2 1 3 1500 2 سهر 1 1000 0 500 200 T 180 CDS-06-431 DEPT-90 T 160 DEPT-135 140 120 100 لك -2 peaks u ppm 80 60 40 20 0COMPOUND 1 INFRARED SPECTRUM 4800 3000 2000 1500 s000 MRVEMUSERI 1906 77 1598 S0 1819 1492 20 1366 1166 77 108? 21 B16 38 798 21 712 50 707 S4 SA7 B4 3270 21 56 1358 53 1345 50 1299 1238 9259 21 COMPOUND 1 2955 74 1029 2939 68 17 66 2924 2054 2727 4. 1454 1408 1378 1209 838 26 42 53 1176 24 10 656 67 49 833 25 620 50QUESTION 5 The IR, 'H NMR and 1°C NMR spectra of compound P are shown below. The molecular formula for compound P is CsH;NO2. Identify three (3) important absorption peaks on the IR spectrum and indicate the bond and wavenumber associated with each peak. Elucidate the structure of compound P and assign each peak in the 'H and 13C NMR spectra. (Hint: The compound consists of more than one functional group). а. b.
- 4. C8H5NO 12 LOD P51381145N141 0 11 HSP-40-439 4000 1 T 10 : T 9 3000 1:3 T 8 7 2000 T 6 ppm 5 4 K NAVENUMSERI- 1500 3 2 1 1000 0 DEPT-90 200 180 DEPT-135 500 COS-09-761 د سل 160 2 5 total peaks 140 ・2 peaks T 120 100 80 ppm 1 →M+₁ 4 total 60 40 20 01000 800 600 400 200 CPS 500 400 300 200 100 -Ó CPS H NMR 60 MHz 250 200 150 100 50 100 50 80 60 20 Integral = 3 40 30 CAH&O2 Integral = 3 Integral = 2 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 O PPM43 184 IR Spectrum (Iquid film) 4000 3000 100 80 60 40 20 40 13C NMR Spectrum (100.0 MHz, CDCI, solution) 9 80 DEPT CH₂ CH₂4 CHA proton decoupled 200 ¹H NMR Spectrum (400 MHz CDCI, solution) expansion 7.5 7.3 ppm 8 P 10 SAMSUNG Galaxy A53 5G 2000 1600 V (cm) 105 M+- 134 120 160 m/e 160 09b0f2ca-eac1-4... 1200 T L 120 2.8 2.7 ppm 7 6 ww 800 Mass Spectrum C10H14 200 240 280 T 1 5 solvent " 80 expansions 1.8 1.7 ppm 1 4 3:54 م 0 *1 470 صفحة Problem 96 UV Spectrum max 260 nm (log10=2.5) PE 40 1.45 1.35 ppm 3 2 Problem 97 08 (ppm) expansion 1.05 0.95 TMS I 0 8 (ppm) 1 202 تمشح بـ 100 جيجابايت تخزين على OneDrive cloud لمدة 6 أشهر 185.
- 100 08 60 40 CH3(CH,),COOH 20 hexanoic acid 1711 1600 wavenumber (cm) 4000 3500 3000 2500 2000 1800 1400 1200 1000 800 600 tTAANSE-TTANCEResolves into 13C NMR Spectrum (50.0 MHz, CDCI, solution) two signals at higher field DEPT CgH11Br Resolves into two signals at higher field expansions proton decoupled solvent 35.0 34.0 ppm 200 160 120 80 40 O 8 (ppm) 1H NMR Spectrum (200 MHz, CDCI, solution) expansion 3.0 2.5 ppm TMS 10 9 8 7 6 5 4 3 2 1 8 (ppm) Determine the structure of the compound based on the above informationMyriam 1718 1. 4000 3000 1600 1200 800 V (cm¹) 100 Mass Spectrum 43 119 80 60 JIK M+* 40 176 20 161 C12 H16 O 40 80 200 280 120 160 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) expansion 188 IR Spectrum (liquid film) % of base peak DEPT CH₂ CH₂ CH proton decoupled L 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) J 1 9 10 I 8 2000 160 the 1 7 6 240 120 130 130 125 ppm 125 ppm L 5 expansion 1 80 1 4 solvent Problem 99 UV Spectrum max 262 nm (log₁0 € 2.5) solvent methanol 40 t I 3 1 2 4 08 (ppm) TMS 1 0 8 (ppm) 1 1 205
- 3. 11 100 TRANSMETTANCE D C8H9CIO 4000 10 HSP-01-151 9 3000 8 2:2 7 2000 6 : 5 ppm 2 NAVENUMBERal 4 3 1500 : Vala 2 1000 3 1 0 500 200 180 COS-04-715 DEPT-90 DEPT-135 160 140 120 بلد لد 100 ppm 80 60 40 20 035 70 105 140 Mass M/e 175 210 1.1 1.0 0.9 0.8 0.7 what functional groups arepresent? 0.6 0.5 0.4 0.3 0.2 500 1000 2000 0 1500 Q.1 500 Wavenumbers (cm-1) Transmitance B57. 200 10 __100_ 140 120 6 100 S 1 13C NMR C12H12 135.39 133.91 129.97 127.39 127.20 126.21 21.69