( find structure Formula: C12H1602IR40003500300025002000wavenumbers (cm)150010001H NMR8= 1.42, 3H,d, J= 6.88= 2.39,3H, s8= 1.17, 3H,1, J= 7.2d= 4.20, 2H,q. J= 7.28= 7.40, 2H,d, J= 8.18= 3.35, IH,9. J= 6.8d=7.20, 2H,d, J= 8.142Ppm (5)1°C NMR: 8 173.0, 137.2, 132.0, 129.7, 129.1, 61.7, 40.5, 25.5, 17.0, 14.1

Answered: Image /qna-images/answer/798f416e-3ef7-4a7f-b9a1-201bca23cb8e.jpg

Formula: C12H1602 DO IR 4000 3500 3000 2500 2000 wavenumbers (cm) 1500 1000 1H NMR 8= 1.42, 3H, d, J= 6.8 8=2.39, 3H, s 8= 1.17, 3H, t, J= 7.2 d= 4.20, 2H, q. J= 7.2 d= 3.35, IH, d= 7.40, 2H, d, J= S.1 9. J= 6.8 d=7.20, 2H, d, J= 8.1 8. 7. 4 Ppem (8) 1°C NMR: 8 173.0, 137.2, 132.0, 129.7, 129.1, 61.7, 40.5, 25.5, 17.0, 14.1

Formula: C12H1602 DO IR 4000 3500 3000 2500 2000 wavenumbers (cm) 1500 1000 1H NMR 8= 1.42, 3H, d, J= 6.8 8=2.39, 3H, s 8= 1.17, 3H, t, J= 7.2 d= 4.20, 2H, q. J= 7.2 d= 3.35, IH, d= 7.40, 2H, d, J= S.1 9. J= 6.8 d=7.20, 2H, d, J= 8.1 8. 7. 4 Ppem (8) 1°C NMR: 8 173.0, 137.2, 132.0, 129.7, 129.1, 61.7, 40.5, 25.5, 17.0, 14.1

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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