FORCES,RESULTANT& ΜΟΜΕNTBF176 DEG2. The forces shown inthe figure are directedat the midpoints of thesides of the triangularA50 DEGF2F1 = 40 KNF2 = 100 KNF3 = 80 KN90°F3rigid body. Compute theAB = 10.46 mBC = 11.20 mresultant of the forces.90°34°CHORIZONTAL

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FORCES, RESULTANT 90° & MOMENT F1 76 DEG 2. The forces shown in A 50 DEG the figure are directed at the midpoints of the sides of the triangular rigid body. Compute the F2 F1 = 40 KN F2 = 100 KN F3 = 80 KN 90° F3 AB = 10.46 m BC = 11.20 m resultant of the forces. 90° 34° C HORIZONTAL

FORCES, RESULTANT 90° & MOMENT F1 76 DEG 2. The forces shown in A 50 DEG the figure are directed at the midpoints of the sides of the triangular rigid body. Compute the F2 F1 = 40 KN F2 = 100 KN F3 = 80 KN 90° F3 AB = 10.46 m BC = 11.20 m resultant of the forces. 90° 34° C HORIZONTAL

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

FORCES,
RESULTANT
& ΜΟΜΕNT
B
F1
76 DEG
2. The forces shown in
the figure are directed
at the midpoints of the
sides of the triangular
A
50 DEG
F2
F1 = 40 KN
F2 = 100 KN
F3 = 80 KN
90°
F3
rigid body. Compute the
AB = 10.46 m
BC = 11.20 m
resultant of the forces.
90°
34°
C
HORIZONTAL

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