Force on q2 by q1 = 89.876 N Force on q, by q2 = 89.876 N O cm 2 10 Charge 1 Charge 2 V Force Values 2 uC 2 uC Scientific Notation -10 10 -10 10 1 cm Figure 1: Simulation setup for Experiment 1 More discussion 5. Determine the electric force direction of q1 and q2 in the above simulation.
Force on q2 by q1 = 89.876 N Force on q, by q2 = 89.876 N O cm 2 10 Charge 1 Charge 2 V Force Values 2 uC 2 uC Scientific Notation -10 10 -10 10 1 cm Figure 1: Simulation setup for Experiment 1 More discussion 5. Determine the electric force direction of q1 and q2 in the above simulation.
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Transcribed Image Text:Force on q2 by q = 89.876 N
Force on q, by q2 = 89.876 N
O cm
2
10
Charge 1
Charge 2
V Force Values
2 µc
2 uC
Scientific Notation
-10
10
-10
10
1 cm
Figure 1: Simulation setup for Experiment 1
More discussion
5. Determine the electric force direction of q1 and q2 in the above simulation.
6. Change q1 to a negative charge. Explain what will happen ie force direction and force
magnitude.
7. Explain why are these electrical force direction only exist in vertical axis only. Can these
forces direction exist in x-axis and/or y-axis? How? Use illustration to support your answer.
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