Force of a Baseball Swing. A baseball has mass 0.145 kg. (a) If the velocity of a pitched ball has a magnitude of 45.0 m/s and the batted ball’s velocity is 55.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. (b) If the ball remains in contact with the bat for 2.00 ms, find the magnitude of the average force applied by the bat.

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Q: A pitcher throws a 0.144-kg baseball toward the batter so that it crosses home plate horizontally…

A: A)Magnitude of impulse = m (v+U)( it is so because the ball is moving along the same path in…

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A: Impulse is nothing but the change in momentum. So all we have to find is the change in the momentum.

Q: (a) What impulse must be imparted to a golf ball of mass 0.041 kg to give it a velocity of 52.9 m/s?…

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Q: a) What impulse is delivered to the ball by the player?  kg·m/s (b) If the player's fist is in…

A: Part A. Impulse = Change in linear momentum Take left direction to be negative and right direction…

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A: (a)   The magnitude of the impulse delivered to the ball can be determined as follows.…

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Q: A 0.263-kg volleyball approaches a player horizontally with a speed of 13.6 m/s. The player strikes…

A: using the basic concept of the Impulse and relation to momentum

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Q: A cruise ship with a mass of 1.00×107 kg strikes a pier at a speed of 0.750 m/s. It comes to rest…

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A: Dear  student The impulse is defined by change in momentum. Also the impulse is given by : J = F∆t =…

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A: The velocity acceleration equation is v2=u2-2asa=u22s And  v=u-att=uat=u2su2=2sut=2×60.75=16s