for x. Round to the nearest tenth of a degree, if necessar 5-3 H 8.5 to

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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### Problem: Solve for \( x \). Round to the nearest tenth of a degree, if necessary.

#### Description:
In this problem, you are provided with a right triangle \( \triangle HFG \). The following dimensions and angle are given:

- \( HG = 5.3 \)
- \( HF = 8.5 \)
- Angle \( HFG = 90^\circ \)
- \( \angle x \) is the angle opposite the side \( HG \) and adjacent to side \( HF \).

The task is to find the value of angle \( x \) in degrees and round it to the nearest tenth if necessary.

#### Diagram:
The triangle is labeled with points H, G, and F such that:
- \( H \) is at the top-left, forming angle \( x^\circ \).
- \( G \) is at the top-right, forming a right angle with H and F.
- \( F \) is at the bottom, forming the hypotenuse with \( H \).

The diagram of the triangle is as follows:

```
H x°
|\
| \
5.3 \ 
|     \
|      \
|       \
|        \
8.5       \
|________________\
F                G
```

#### Steps to Solve for \( x \):

1. **Identify the Trigonometric Function:**
   Since angle \( x \) is opposite side \( HG \) and adjacent to side \( HF \), you can use the tangent function:
   \[
   \tan(x) = \frac{\text{opposite}}{\text{adjacent}} = \frac{HG}{HF}
   \]

2. **Calculate the Tangent:**
   Substitute the given values:
   \[
   \tan(x) = \frac{5.3}{8.5}
   \]

3. **Compute the Value:**
   \[
   \tan(x) \approx 0.6235
   \]

4. **Find the Angle:**
   Use the inverse tangent (arctan) function to find the angle \( x \):
   \[
   x = \tan^{-1}(0.6235)
   \]
   
   Using a calculator:
   \[
   x \approx 32.1^\circ
   \]

#### Solution:
The angle \( x \) is approximately \( 32.1^\circ \).
Transcribed Image Text:### Problem: Solve for \( x \). Round to the nearest tenth of a degree, if necessary. #### Description: In this problem, you are provided with a right triangle \( \triangle HFG \). The following dimensions and angle are given: - \( HG = 5.3 \) - \( HF = 8.5 \) - Angle \( HFG = 90^\circ \) - \( \angle x \) is the angle opposite the side \( HG \) and adjacent to side \( HF \). The task is to find the value of angle \( x \) in degrees and round it to the nearest tenth if necessary. #### Diagram: The triangle is labeled with points H, G, and F such that: - \( H \) is at the top-left, forming angle \( x^\circ \). - \( G \) is at the top-right, forming a right angle with H and F. - \( F \) is at the bottom, forming the hypotenuse with \( H \). The diagram of the triangle is as follows: ``` H x° |\ | \ 5.3 \ | \ | \ | \ | \ 8.5 \ |________________\ F G ``` #### Steps to Solve for \( x \): 1. **Identify the Trigonometric Function:** Since angle \( x \) is opposite side \( HG \) and adjacent to side \( HF \), you can use the tangent function: \[ \tan(x) = \frac{\text{opposite}}{\text{adjacent}} = \frac{HG}{HF} \] 2. **Calculate the Tangent:** Substitute the given values: \[ \tan(x) = \frac{5.3}{8.5} \] 3. **Compute the Value:** \[ \tan(x) \approx 0.6235 \] 4. **Find the Angle:** Use the inverse tangent (arctan) function to find the angle \( x \): \[ x = \tan^{-1}(0.6235) \] Using a calculator: \[ x \approx 32.1^\circ \] #### Solution: The angle \( x \) is approximately \( 32.1^\circ \).
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