Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- 9. (a) Sketch the Mode I, Mode II, and Mode III crack opening geometries, and clearly state which is the most commonly found in engineering structures. (b) Define plane stress and plane strain, making clear which, if any, of the stresses are zero in each case. (c) What is plane strain fracture toughness? 10. (a) Write Griffith's expression for the fracture stress of a material under plane stress conditions. Identify which parameters are applied and which are material constants. (b) What is the leak-before-break condition? Please explain. Iarrow_forwardConsider a single crystal oriented such that the slip direction and normal to the slip plane are at angles 42.7° and 48.3°, respectively, with the tensile axis. If the critical resolved shear stress is 26.3 MPa, what applied stress (in MPa) will be necessary to cause the single crystal to yield? i MPaarrow_forwardA very large, steel plate of yield stress 200 MPa has a crack at the centre of length 18 mm, orientated along the x-axis. If the plate is subjected to far field tensile loading of magnitude 179 MPa and is assumed to be in a state of plane strain, determine the extent of the plastic region at the crack tip, along the x-axis. You may assume Poisson's ratio is (1/3). Express your answer as an integer value of mm.arrow_forward
- A rectangular thin plate with Young's modulus 200 GPa and Poisson's ratio 0.30 is subjected to uniform stress distribution at its edges as shown. However it is stated that the dimension b of the plate does not change under the action of stress components , and om Considering microstrains (in 106), the change in the length of dimension a (in mm) is (rounded off to three decimal places) b- 100 mm O= 200 MPa Oyy = 200 mmarrow_forwardAt a point in a machine component that is subjected to plane stress, the normal and shear stresses are σx= 100 MPa, σy= 35 MPa, and τxy= 70 MPa, acting in the directions shown in the figure. At this point, determine the strain components εx, εy, εz, and γxy. Assume that E = 72 GPa and v = 0.30 for the machine component.arrow_forwardA solid cylindrical shaft has a diameter of d = 20 mm and is made from steel with an ultimate strength of Su = 850 MPa. For each of the following conditions, determine the safety factor (n) with respect to infinite fatigue life (endurance strength Se) and fracture strength (Sf) at 5 × 10¹ cycles. The loading is applied at room temperature 100 Nm (no axial load or torsion), a cold-drawn surface (a) With a bending moment of M = finish and a reliability of 95%. (b) With a torsional load of T = 200 Nm (no axial load or bending), a ground surface finish and a reliability of 99%. M T T ( Marrow_forward
- Problem 1. A material element in plane stress is subjected to stresses: Ox = -7000 psi Oy = -3000 psi = -4000 psi Txy а) Find the stresses ox,, Oy,, and Tx, y, on an element oriented at an angle 0 = 30° clockwise from the x axis and show these stresses and on a sketch of a properly oriented element. b) Find the principal stress angles, Op1, Op2, and the principal stresses, 01,02 c) Find the maximum shear stress angles, 051, es2, and the maximum shear stresses, +Tmax- d) Show the principal stresses and maximum shear stresses on a sketch of a properly oriented elementarrow_forwardPlease no hand writing solution for other wise down votearrow_forwardBased in the table 1.1) Develop a best-fit equation for the relationship between stress and strain. Employ Naïve–Gauss elimination method whenever necessary.S=______+______e + _______e2 2) Determine the coefficient of determination for the equation. R2 =_______ 3) Calculate the stress value to the most accurate value at strain value 0.53.s = _______Pa4) The yield point is the point on a stress–strain curve that indicates the limit of elastic behaviour and the beginning of plastic behavior. In this case, the yield point occurs at a stress value of 80. Determine the corresponding strain value at the yield point. In any relevant method, use a stopping criterion of 0.05% e =_______ 5) The ultimate strength is the maximum point on the stress–strain curve. This corresponds to the maximum stress that can be sustained by a structure in tension. Compute the ultimate strength point of the polymeric material (strain value that gives maximum stress). In any relevant method, use a stopping…arrow_forward
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