For the zero-order reaction below, a graph of rate = k[A]° versus time will generate a straight line. A B+C Select one: O a. [A]; O . [] In [A]. O c. In[A], O d. 1 [A], O e. In(2) [A],

For a reaction with the rate law below: Rate = k[A]? %3D a plot of In[A] vs. time gives a straight line. a plot of 1/[A] vs. time gives a straight line. a plot of 1/[A] vs. 1/time gives a straight line. O a plot of [A] vs. time gives a straight line. O a plot of log [A]o/[A] vs. 1/time gives a straight line. A Moving to another question will save this response. esc 20 F3 F1 F4 $4 1. 2. 4 Q W R. # 3

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3. You have a reaction that is run at 273°C and has a rate constant of 2.52 x 10/s. The same reaction is run at 157 °C and has a rate constant of 1.0 x 10-/s. What is the activation energy for this reaction? (R = 8.314 J/mol K) %3D 0.00898mols 102 sec 4. w for ate= k[NO2]?. The rate constant for this reaction: If yo tion for 5 minutes urd be the concentra