For the system shown in the figure, the cylinder rolls without slipping. What is the acceleration of mass M/4? T M M/4| ICM=1/2 MR?
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![For the system shown in the figure, the cylinder rolls without slipping. WWhat is the
acceleration of mass M/4?
R
T
M
M/4
ICM=1/2 MR²
g
g/3
3g/4
2g/3
g/2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c360319-dba5-4ec3-8d3b-73199a71daf8%2Ffb513af7-2bec-4572-814d-21ac7a2649c3%2Fuerf7a_processed.png&w=3840&q=75)
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