For the sample data given in worksheet 2.5a. Check the data for normality.b. Use MINITAB to test the hypotheses Hoμ = 200 versus H₁ μ 200 at α = 0.05. Is theresufficient evidence to reject Ho?c. Confirm the confidence interval for the mean by manual calculation.d. Confirm the hypothesis test's t statistic by manual calculation and compare it to the critical t0.025value for the test. →>>C1Volts86.486.512386.5483.8588.3687.0785.3883.4985.81085.31188.91285.81386.81483.715165685.286.81786.71886.61984.62087.82184.02285.12384.22485.22587.126

Sure, to proceed with the analysis, we'll use hypothetical data since the actual data isn't…

Answered: For the sample data given in worksheet…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You wish to test the following claim (HaHa) at a significance level of α=0.02. Ho:μ=88.1 Ha:μ≠88.1You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=74n=74 with mean M=81.2M=81.2 and a standard deviation of SD=16.9SD=16.9.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 88.1. There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 88.1. The sample data support the claim that the…
You wish to test the following claim (HaHa) at a significance level of α=0.10α=0.10. Ho:μ=59.9 Ha:μ>59.9You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=104 with mean M=62.7 and a standard deviation of SD=10.2.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = ________What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =_____________
5. Consider the following estimated equation that is used to study the effect of skipping class on college GPA: colGPA= 1.39+ .412 hsGPA+ .015 ACT- .083 skipped (.011) (33) (.094) (.026) n= 141, R= 234 (1) Using the standard normal approximation, find the 95% confidence interval for GPA (2) Based on the 95% confidence interval you obtained, can you reject the hypothesis H: PisGPA 0.4against the two-sided alternative at the 5% level? (3) Can you reject the hypothesis H BGPA 0.1 at the 5% level? (4) Can you reject the hypothesis Ho PGPA 0.8 at the 5% level?
The mean number of eggs per person eaten in the United States is 224. Do college students eat less eggs than the average American? The 46 college students surveyed averaged 205 eggs per person and their standard deviation was 61.4. What can be concluded at the αα = 0.05 level of significance? For this study, we should use z-test for a population proportion or t-test for a population mean. The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer = > ≠ < H1:H1: ? p μ Select an answer > = ≠ < The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should; fail to reject, accept, or reject the null hypothesis.
5. Consider the following estimated equation that is used to study the effect of skipping class on colege GPA: COLGPA- 1.39+412 HSGPA+015 ACT - 083 skipped (011) (.026) (33) (.094) n= 141, R2= 234 (1) Using the standard normal approximation, find the 95% confidence interval for puA (2) Based on the 95% confidence interval you obtained, can you reject the hypothesis H BOPA = 0.4 against the two-sided alternative at the 5% level? (3) Can you reject the hypothesis H: PPA = 0.1 at the 5% level? (4) Can you reject the hypothesis H,: P 0.8 at the 5% level?
Use a 0.05 significance level to test the claim that there is a difference between the actual and reported heights, in inches, for 12-16 year old boys. The data is listed in the table below. Click the icon to view the data table of the reported heights. Let μ₁ denote the median of the first variable and μ₂ denote the median of the second variable. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: H₁ H₂ C. Ho: H₁ H2 H₁: H₁ H₂ Find the test statistic. Test statistic = -2.26 (Round to two decimal places as needed.) CH More Info OB. Ho: H₁ H₂ H₁: P1 P₂ OD. Ho: ₁2H₂ H₁ H₁ H₂ Actual 61.9 67.9 71.2 61.4 62.3 68.8 65.9 70.8 61.9 66.7 Reported 62 68 71 62 61 69 66 70 62 67 Actual 59.6 71.9 64.5 64.4 71.9 69.1 68.8 68.1 71.7 62.5 Reported 60 72 64 64 72 69 68 68 72 62 Actual 65.2 59.9 64.8 65.5 67 Reported 65 60 65 66 67 Print 68.7 65.2 71.4 69.2 60.9 69 65 72 69 61 Done - X
You wish to test the following claim (Hα) at a significance level of α=0.02 Ho : =μ 55.7 Ha : ≠ μ 55.7 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=33 with mean M= 45.9 and a standard deviation of SD = 14.8. What is the test statistic for this sample? What is the p-value for this sample? Is the P value less than, greater than, or equal to α? This test statistic leads to a decision to... The final conclusion is?
Use the pulse rates in beats per minute (bpm) of a random sample of adult females listed in the data set available below to test the claim that the mean is less than 79 bpm. Use a 0.05 significance level. LOADING... Click the icon to view the pulse rate data. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0: μ=79 bpm H1: μ≠79 bpm B. H0: μ>79 bpm H1: μ<79 bpm C. H0: μ=79 bpm H1: μ<79 bpm D. H0: μ=79 bpm H1: μ>79 bpm Determine the test statistic. nothing (Round to two decimal places as needed.) Determine the P-value. nothing (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. ▼ Reject Fail to reject H0. There is ▼ not sufficient sufficient evidence to conclude that the mean of the population of pulse rates for adult females is ▼ greater than not less than…
In a certain large city the mean birth weight of babies is 7.1 pounds with a standard deviation of 1.2 pounds. You believe that in one neighborhood in the city the mean birth weight is different from 7.1 pounds. You sample 95 births and find the mean weight of the sample to be 7.4 pounds. Can the claim be supported to a level of significance of α = .05, test the hypothesis?
LSU's Ag. Center wants to determine whether the mean yield for sugarcane is different this year compared to the historical avg of 8,700 lbs of sugar per acre. Thus, the null and alternative hypotheses are Ho: mu = 8,700 Ha: mu is not = to 8,700 You set out to conduct a hypothesis test at the 95% level. Mean yields are distributed Normally. You take a sample of 100 different acres. From this sample, you calculate a mean yield of 8,853 and a std deviation of 1,150. What is the test statistic for this hypothesis test? (To two decimal places. ex: 1.23)
LSU's Ag. Center wants to determine whether the mean yield for sugarcane is different this year compared to the historical avg of 8,700 lbs of sugar per acre. Thus, the null and alternative hypotheses are Ho: mu = 8,700 Ha: mu is not = to 8,700 You set out to conduct a hypothesis test at the 95% level. Mean yields are distributed Normally. You take a sample of 100 different acres. From this sample, you calculate a mean yield of 8,853 and a std deviation of 1,150. What are the bounds for the acceptance region for this hypothesis test? Group of answer choices -1.64 to 1.64 -2.58 to 2.58 -1.33 to 1.33 -1.96 and 1.96
LSU's Ag. Center wants to determine whether the mean yield for sugarcane is different this year compared to the historical avg of 8,700 lbs of sugar per acre. Thus, the null and alternative hypotheses are Ho: mu = 8,700 Ha: mu is not = to 8,700 You set out to conduct a hypothesis test at the 95% level. Mean yields are distributed Normally. You take a sample of 100 different acres. From this sample, you calculate a mean yield of 8,853 and a std deviation of 1,150. Do you reject or not-reject the null hypothesis?

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